Math Problem Statement

Write a cosine function that has an amplitude of 3, a midline of y=4 and a period of 2pi

Solution

To write the equation of a cosine function with the given characteristics:

  • Amplitude: 33
  • Midline: y=4y = 4
  • Period: 2π2\pi

The general form of a cosine function is:

y=Acos(Bx+C)+Dy = A \cos(Bx + C) + D

Where:

  • AA is the amplitude.
  • BB is related to the period by the formula Period=2πB\text{Period} = \frac{2\pi}{B}.
  • DD is the vertical shift (midline).

Given the information:

  • A=3A = 3
  • The period is 2π2\pi, so B=1B = 1 (since 2πB=2π\frac{2\pi}{B} = 2\pi implies B=1B = 1).
  • D=4D = 4

Assuming there is no phase shift (i.e., C=0C = 0), the equation of the cosine function is:

y=3cos(x)+4y = 3 \cos(x) + 4

Would you like to dive deeper into any of these details or have further questions?

Here are 5 related questions to consider:

  1. How would the function change if the amplitude were reduced to 1?
  2. What is the effect on the graph if the midline is changed to y=0y = 0?
  3. How would the equation look if the period were π\pi instead of 2π2\pi?
  4. What would the phase shift be if C=π2C = \frac{\pi}{2}?
  5. How do you determine the maximum and minimum points of this cosine function?

Tip: Remember, for trigonometric functions, changing the period affects the frequency of the function, while changing the midline affects its vertical position on the graph.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Cosine Function

Formulas

General form of cosine function: y = A cos(Bx + C) + D
Period formula: Period = 2π / B

Theorems

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Suitable Grade Level

Grades 10-12