Math Problem Statement

Two workers Bumrah and Siraj can complete a piece of work in 40 days if they work alternately starting with Bumrah and followed by Siraj. Bumrah takes ‘p’ days to complete the same work working alone while Siraj takes ‘q’ days to complete the same work working alone. If p and q are integers, then how many ordered pairs of (p, q) are possible?

Solution

The problem states:

  • Bumrah and Siraj alternate to complete a piece of work in 40 days. Bumrah takes p days to finish the work alone, and Siraj takes q days. We are asked to find how many ordered pairs of integers (p,q)(p, q) are possible.

Let's break down the problem:

  • Bumrah works for a day, then Siraj works for a day, and so on.

  • The total work done by both in 1 day is: 1p+1q\frac{1}{p} + \frac{1}{q} This represents the part of work they complete together in 1 day when working alternately.

  • Since they alternate, the combined work of 2 days will be: 1p+1q\frac{1}{p} + \frac{1}{q} Therefore, in 40 days, they alternate for 20 cycles (each cycle is 2 days).

  • In 40 days, the fraction of work completed by them will be: 20×(1p+1q)=1(since they complete the entire work in 40 days)20 \times \left(\frac{1}{p} + \frac{1}{q}\right) = 1 \quad \text{(since they complete the entire work in 40 days)}

  • Simplifying, we get: 20p+20q=1\frac{20}{p} + \frac{20}{q} = 1

  • Multiplying through by pqpq to eliminate the fractions: 20q+20p=pq20q + 20p = pq Rearranging this equation: pq20p20q=0pq - 20p - 20q = 0 Adding 400 to both sides to factorize: pq20p20q+400=400pq - 20p - 20q + 400 = 400 This gives: (p20)(q20)=400(p - 20)(q - 20) = 400

Now, we need to find how many ordered pairs of integers (p,q)(p, q) are possible by solving (p20)(q20)=400(p - 20)(q - 20) = 400.

The number of divisors of 400 will give us the number of factorizations of the equation above.

Divisors of 400:

The prime factorization of 400 is: 400=24×52400 = 2^4 \times 5^2 The number of divisors is given by: (4+1)(2+1)=5×3=15(4 + 1)(2 + 1) = 5 \times 3 = 15 So, there are 15 divisors of 400.

Conclusion:

Since each divisor gives us a pair (p,q)(p, q), there are 15 ordered pairs of integers (p,q)(p, q).

Thus, the correct answer is (D) 15.


Do you want further details or have any questions about this problem?

Here are 5 related questions to extend your understanding:

  1. How do you find the prime factorization of a number?
  2. What is the formula for finding the number of divisors of a number based on its prime factorization?
  3. How would the answer change if Bumrah and Siraj alternated working every half-day instead of every day?
  4. How can you use algebraic manipulation to solve similar work-time problems?
  5. What role does symmetry play in finding factor pairs of numbers?

Tip: Always try to express work-rate problems in terms of "work done per unit time" to simplify calculations.

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Math Problem Analysis

Mathematical Concepts

Work Rate Problems
Algebra
Factorization

Formulas

Work rate formula: 1/p + 1/q
Prime factorization of a number

Theorems

Divisor theorem (to find number of divisors from prime factorization)

Suitable Grade Level

Grades 9-12