Math Problem Statement
A tank that resembles a hemisphere flat face up is full of water, with a small outlet on the top right. The weight of water is 62.5 lb/ft^3, find the work required to pump the water out of the outlet.
Solution
To find the work required to pump the water out of a hemispherical tank with a small outlet at the top, we need to use the concept of work in the context of pumping liquids. The work is calculated by integrating the force exerted over a distance. Here's how we can solve this step-by-step:
1. Define the Problem:
- Shape of the Tank: Hemisphere with the flat face up.
- Weight of Water: lb/ft³.
- Radius of the Hemisphere: Let’s denote it as .
2. Determine the Differential Element:
Consider a thin horizontal slice of water at a height from the bottom of the tank, where the bottom of the hemisphere is at and the top of the hemisphere is at .
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Thickness of the slice: .
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Volume of the slice: This can be represented as the area of the circular cross-section at height times the thickness .
The area of the cross-section is given by the formula for the area of a circle with radius (since the radius at height decreases as we move up).
So, the volume of the slice is:
3. Calculate the Weight of the Slice:
The weight of this thin slice is given by the density of water times the volume:
4. Calculate the Work to Pump this Slice to the Top:
To find the work required to pump this slice out of the outlet at the top, we need to move it a distance of . The work to move the slice is given by:
5. Integrate Over the Entire Volume:
To find the total work, we integrate from to :
6. Evaluate the Integral:
Simplifying the integral:
Let's break it down:
Substitute and :
Combine like terms:
Finally, multiply by the constant:
So, the total work required is:
This gives the amount of work needed to pump all the water out of the hemisphere.
Questions to Consider:
- How would the work change if the outlet was at the center of the flat face instead of the top right?
- What happens to the work required if the tank was not full?
- How would this problem differ if the tank was a full sphere?
- What if the density of the fluid was different?
- How does the shape of the tank influence the required work?
Tip:
Always break down the integral into simpler parts to avoid mistakes in complex expressions!
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Math Problem Analysis
Mathematical Concepts
Calculus
Integration
Work-Energy Principle
Volume of Revolution
Formulas
Work = Force * Distance
Volume of a thin slice of water: dV = π(R^2 - y^2) dy
Force = Weight Density * Volume
Work for a slice: dW = 62.5 * π(R^2 - y^2) (R - y) dy
Total Work: W = ∫_0^R 62.5 * π (R^2 - y^2) (R - y) dy
Theorems
Fundamental Theorem of Calculus
Suitable Grade Level
University Level (Calculus)
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