Math Problem Statement
Solution
To find the volume under the surface and above the given rectangular region with boundaries and , we need to set up and evaluate a double integral.
The volume under the surface is given by:
Let's break this down step-by-step:
1. Inner integral with respect to :
First, compute the integral .
Now evaluate this expression from to :
[ \left[ (3)^2 + (5y + 2)(3) \right] - \left[ (-1)^2 + (5y + 2)(-1) \right] ]
[ = \left[ 9 + 3(5y + 2) \right] - \left[ 1 - (5y + 2) \right] ]
[ = \left[ 9 + 15y + 6 \right] - \left[ 1 - 5y - 2 \right] ]
So the result of the inner integral is .
2. Outer integral with respect to :
Now, integrate with respect to :
Now evaluate this expression from to :
[ = \left[ 16(4) + 10(4)^2 \right] - \left[ 16(3) + 10(3)^2 \right] ]
[ = \left[ 64 + 10(16) \right] - \left[ 48 + 10(9) \right] ]
[ = \left[ 64 + 160 \right] - \left[ 48 + 90 \right] ]
Final Answer:
The volume under the surface is cubic units.
Would you like a further breakdown of any part of the solution?
Here are 5 related questions for deeper understanding:
- How would the volume change if the surface equation were different, for example, ?
- What is the geometric meaning of evaluating this double integral?
- How can this problem be solved using numerical methods instead of symbolic integration?
- What if the boundaries were shifted, such as and ?
- How can the concept of double integrals be applied in real-world problems?
Tip: For complicated regions or functions, breaking down double integrals into smaller steps often makes the computation easier!
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Math Problem Analysis
Mathematical Concepts
Double Integration
Volume under Surface
Multivariable Calculus
Formulas
V = \int_{y=3}^{4} \int_{x=-1}^{3} (2x + 5y + 2) dx dy
Inner integral: \int_{-1}^{3} (2x + 5y + 2) dx
Outer integral: \int_{3}^{4} (16 + 20y) dy
Theorems
Fubini's Theorem
Suitable Grade Level
University Level - Calculus II or Multivariable Calculus