Find the volume and surface area of the right circular cylinder.

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Part 1

Volumealmost equals≈enter your response here 

inincubed3

​(Use 3.14 for 

piπ. 

Round to the nearest​ tenth.)

Part 2

Surface 

areaalmost equals≈enter your response here 

ininsquared2

​(Use 3.14 for 

piπ. 

Round to the nearest​ tenth.)

To find the **volume** and **surface area** of a right circular cylinder, we use the following formulas:

### 1. **Volume of the Cylinder**:
The formula for the volume \( V \) is:
\[
V = \pi r^2 h
\]
where:
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder, and
- \( \pi \approx 3.14 \) (as per the question).

### 2. **Surface Area of the Cylinder**:
The formula for the surface area \( A \) is:
\[
A = 2\pi r^2 + 2\pi rh
\]
where:
- \( 2\pi r^2 \) represents the area of the two circular bases,
- \( 2\pi rh \) represents the lateral surface area of the cylinder.

#### Information Needed:
- The **radius \( r \)** of the base,
- The **height \( h \)** of the cylinder.

If you provide the values for \( r \) and \( h \), I can calculate the exact volume and surface area for you.

Would you like to provide those values? Let me know if you need any details!

---

### Further questions:
1. What is the radius and height of the cylinder in this problem?
2. Do you need a breakdown of the calculations for both volume and surface area?
3. How would you approach the surface area if the cylinder had no top base?
4. Why does the surface area formula have two components?
5. How does rounding affect the final result?

**Tip**: Always keep track of units while calculating volume and surface area to avoid mistakes!

Find the volume and surface area of the right circular cylinder. Volume ≈ ___ in³ (Use 3.14 for π. Round to the nearest tenth.) Surface area ≈ ___ in² (Use 3.14 for π. Round to the nearest tenth.)

Learn how to find the volume and surface area of a right circular cylinder using π ≈ 3.14. This guide includes key geometry concepts and the formulas V = πr²h for volume and A = 2πr² + 2πrh for surface area. Suitable for students in Grades 6-8, with step-by-step calculations rounded to the nearest tenth.

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