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The image shows a problem about Piper's ping-pong team and a box of ping-pong balls.

### Problem 1a:
We need to find how many ping-pong balls fit in the box. Each ball occupies a space of 1 unit x 1 unit x 1 unit, and the box is represented by a grid in the shape of a rectangular prism.

To solve for the number of ping-pong balls the box can hold, we can calculate the **volume** of the box in terms of the number of unit cubes (since each ball occupies 1 unit cube).

Looking closely at the box grid in the image, we can estimate the dimensions of the box:
- **Length**: 10 units
- **Width**: 6 units
- **Height**: 4 units

So, the total number of ping-pong balls is calculated by the volume of the box:
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height} = 10 \times 6 \times 4 = 240
\]
Thus, the box holds **240 ping-pong balls**.

### Problem 1b:
To determine how much cardboard is needed to make the box, we need to calculate the **surface area** of the box. The surface area is the sum of the areas of all six faces of the rectangular prism.

The formula for surface area \(S\) of a rectangular prism is:
\[
S = 2(\text{Length} \times \text{Width}) + 2(\text{Length} \times \text{Height}) + 2(\text{Width} \times \text{Height})
\]

Using the dimensions:
- Length = 10 units
- Width = 6 units
- Height = 4 units

Substitute into the surface area formula:
\[
S = 2(10 \times 6) + 2(10 \times 4) + 2(6 \times 4)
\]
\[
S = 2(60) + 2(40) + 2(24) = 120 + 80 + 48 = 248
\]

Thus, it would take **248 square units** of cardboard to make the box.

---

Would you like more details or explanations on any part? Here are some related questions:

1. What is the difference between volume and surface area?
2. How do you calculate the volume of different shapes?
3. How does changing one dimension affect the volume and surface area of a box?
4. How can we use the concept of volume in real-life packing problems?
5. How would the cardboard required change if the box's dimensions doubled?

**Tip**: Surface area measures the material needed to cover the outside of a shape, while volume measures the space inside it.

Piper's Ping-Pong Team problem asking how many ping-pong balls fit in a box and how much cardboard is needed to make the box.

Solve how many ping-pong balls fit in a rectangular box and how much cardboard is needed to make the box. This problem teaches students in Grades 4-6 key concepts like volume and surface area of rectangular prisms.

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