Math Problem Statement

Find the volume of the given solid region in the first octant bounded by the plane 12 x plus 20 y plus 15 z equals 60 and the coordinate​ planes, using triple integrals. left parenthesis 5 comma 0 comma 0 right parenthesis left parenthesis 0 comma 3 comma 0 right parenthesis left parenthesis 0 comma 0 comma 4 right parenthesis Question content area bottom Part 1 Complete the triple integral below used to find the volume of the given solid region. Note the order of integration dz dy dx. VequalsIntegral from 0 to nothing Integral from 0 to nothing Integral from 0 to nothing dz dy dx         

Solution

To find the volume of the given solid region in the first octant bounded by the plane 12x+20y+15z=6012x + 20y + 15z = 60 and the coordinate planes using a triple integral, we need to set up the integral properly.

Step 1: Rewrite the plane equation for bounds

The equation of the plane is: 12x+20y+15z=6012x + 20y + 15z = 60 Let's solve for zz in terms of xx and yy: z=6012x20y15=44x54y3z = \frac{60 - 12x - 20y}{15} = 4 - \frac{4x}{5} - \frac{4y}{3}

Step 2: Determine the limits of integration

Since we are considering the first octant, the limits for xx, yy, and zz are from 0 to their respective bounds:

  • For xx, the intersection with the xx-axis gives x=5x = 5 when y=0y = 0 and z=0z = 0.
  • For yy, the intersection with the yy-axis gives y=3y = 3 when x=0x = 0 and z=0z = 0.
  • For zz, it ranges from 0 to 44x54y34 - \frac{4x}{5} - \frac{4y}{3}.

Step 3: Set up the triple integral

The volume VV can be found using the triple integral dzdydx\int \int \int \, dz \, dy \, dx.

V=05033x5044x54y3dzdydxV = \int_{0}^{5} \int_{0}^{3 - \frac{3x}{5}} \int_{0}^{4 - \frac{4x}{5} - \frac{4y}{3}} dz \, dy \, dx

Step 4: Complete the integral limits

  • The outermost integral with respect to xx is from 00 to 55.
  • The middle integral with respect to yy is from 00 to 33x53 - \frac{3x}{5}.
  • The innermost integral with respect to zz is from 00 to 44x54y34 - \frac{4x}{5} - \frac{4y}{3}.

Thus, the complete triple integral is: V=05033x5044x54y3dzdydxV = \int_{0}^{5} \int_{0}^{3 - \frac{3x}{5}} \int_{0}^{4 - \frac{4x}{5} - \frac{4y}{3}} dz \, dy \, dx

Would you like a step-by-step solution to evaluate this integral?

Related Questions:

  1. What is the geometric interpretation of a triple integral in this context?
  2. How would you evaluate the volume if the plane equation was different?
  3. How does the order of integration (e.g., dzdxdydz \, dx \, dy) affect the computation?
  4. What are the limits of integration for a different solid region bounded by another plane?
  5. Can we use cylindrical or spherical coordinates for this volume calculation?

Tip:

When setting up triple integrals for volumes, always sketch the region and understand the plane intersections to set accurate bounds.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Triple Integrals
Volume Calculation
Plane Intersections

Formulas

Equation of the plane: 12x + 20y + 15z = 60
Triple integral setup: V = ∫∫∫ dz dy dx
Bounds derived from intersections with axes and the plane

Theorems

Fundamental Theorem of Calculus for triple integrals
Limits of integration based on bounding planes and intersections

Suitable Grade Level

College-level Calculus (Multivariable Calculus)