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The problem asks to find the volume of a solid using cylindrical coordinates. The solid is bounded by the following surfaces:

1. The equation of a sphere: \(x^2 + y^2 + z^2 = 2z\), which simplifies to \((x^2 + y^2) + (z - 1)^2 = 1\). This describes a sphere of radius 1, centered at \((0, 0, 1)\).
   
2. The surface given by \(z = \sqrt{x^2 + y^2}\), which is a cone in cylindrical coordinates.

Now, let's solve this step by step:

### 1. Rewrite in Cylindrical Coordinates:
In cylindrical coordinates, the transformations are:
\[
x = r \cos(\theta), \quad y = r \sin(\theta), \quad z = z
\]
where \(r = \sqrt{x^2 + y^2}\).

The equations become:

- For the sphere: \((x^2 + y^2) + (z - 1)^2 = 1\) becomes \(r^2 + (z - 1)^2 = 1\).
- For the cone: \(z = \sqrt{x^2 + y^2} = r\).

### 2. Find the Region of Integration:
From the sphere equation \(r^2 + (z - 1)^2 = 1\), we solve for \(z\):
\[
z = 1 \pm \sqrt{1 - r^2}
\]
Thus, the upper boundary of \(z\) is \(z = 1 + \sqrt{1 - r^2}\) and the lower boundary is \(z = 1 - \sqrt{1 - r^2}\), but we are only interested in the portion below the cone, where \(z = r\).

### 3. Volume Integral in Cylindrical Coordinates:
The volume integral in cylindrical coordinates is given by:
\[
V = \int_{\theta=0}^{2\pi} \int_{r=0}^{1} \int_{z=r}^{1 + \sqrt{1 - r^2}} r \, dz \, dr \, d\theta
\]
Here, \(r \, dz \, dr \, d\theta\) is the volume element in cylindrical coordinates.

### 4. Compute the Volume:
Let's proceed to compute this integral step by step. I will calculate it for you.

The volume of the solid bounded by the given surfaces, computed using cylindrical coordinates, is \( \pi \) cubic units.

Would you like more details on the steps or any specific clarifications?

Here are five related questions to expand on the topic:

1. How do cylindrical coordinates simplify volume integrals in problems with symmetry?
2. How would the integral change if the solid had different boundary surfaces?
3. Can this problem be solved using spherical coordinates, and how would the approach differ?
4. How is the Jacobian determinant used when converting from Cartesian to cylindrical coordinates?
5. What are other common examples of solids where cylindrical coordinates are useful?

**Tip:** When solving volume problems with symmetry, choosing the appropriate coordinate system (like cylindrical or spherical) often simplifies the integral significantly.

Utilice coordenadas cilíndricas para hallar el volumen del sólido que se encuentra limitado por las superficies de ecuaciones: x^2 + y^2 + z^2 = 2z y z = sqrt(x^2 + y^2).

Solve for the volume of a solid bounded by a sphere and a cone using cylindrical coordinates. Explore key multivariable calculus concepts and integration methods in cylindrical systems. Ideal for Calculus III students.

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