https://file.aiquickdraw.com/mathbot/file/1729845914196yb0idrzz.jpg

To find the volume of a sphere, we use the formula:

\[
V = \frac{4}{3} \pi r^3
\]

Where:
- \( r \) is the radius of the sphere.
- \( \pi \) is approximately 3.14.

From the problem, the diameter of the ball is 21 cm, so the radius is:

\[
r = \frac{21}{2} = 10.5 \, \text{cm}
\]

Now, substituting the values into the formula:

\[
V = \frac{4}{3} \times 3.14 \times (10.5)^3
\]

First, calculate \( (10.5)^3 \):

\[
10.5^3 = 1157.625
\]

Then, substitute back:

\[
V = \frac{4}{3} \times 3.14 \times 1157.625
\]

Now simplify:

\[
V = \frac{4}{3} \times 3634.94 = 4846.59 \, \text{cm}^3
\]

So, the volume of the ball is approximately **4846.59 cm³**.

Would you like more details or have any questions? Here are some related questions:

1. How does the volume of a sphere change if the radius is doubled?
2. How do you find the surface area of a sphere?
3. What is the relationship between the volume and surface area of a sphere?
4. Can you compare the volume of this sphere with a cylinder of the same height?
5. How would the volume change if the diameter were given in meters?

**Tip:** When working with spheres, always remember that volume increases with the cube of the radius, so even small changes in radius result in large changes in volume.

A sports ball has a diameter of 21 cm. Find the volume of the ball. Round your answer to 2 decimal places, and use 3.14 as an approximation of π.

Calculate the volume of a sphere with a diameter of 21 cm. Learn to use the formula V = (4/3)πr^3 and round the result to two decimal places. A great problem for students in Grades 8-10.

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