To find the volume of a cone, we use the formula:

$V = \frac{1}{3} \pi r^2 h$

Where:

• $r$ is the radius of the cone,
• $h$ is the height of the cone, and
• $\pi$ is either left as a symbol or approximated as 3.14.

Given:

• $r = 5$ units,
• $h = 3$ units.

Now, substitute these values into the formula:

$V = \frac{1}{3} \pi (5)^2 (3)$

Simplify:

$V = \frac{1}{3} \pi (25) (3) = \frac{1}{3} \pi (75) = 25 \pi \, \text{cubic units}$

If you use $\pi = 3.14$, the volume is approximately:

$V \approx 25 \times 3.14 = 78.5 \, \text{cubic units}$

The volume is:

• Exact form: $25 \pi \, \text{cubic units}$,
• Approximate form: $78.5 \, \text{cubic units}$.

Would you like more details or have any questions?

Here are 5 related questions:

1. What happens to the volume if the radius is doubled?
2. How would the volume change if the height were 5 units instead of 3?
3. Can you calculate the surface area of the same cone?
4. How does the formula for the volume of a cone compare to that of a cylinder?
5. What is the volume of a cone with a radius of 10 units and a height of 4 units?

Tip: Remember that the volume of a cone is always one-third that of a cylinder with the same base and height!