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The problem shown in the image asks to find the volume of a cone with a radius of 18 feet and a height of 11 feet. The task also requests to provide both the exact value (in terms of π) and an approximation to the nearest hundredth.

The formula for the volume \( V \) of a cone is:

\[
V = \frac{1}{3} \pi r^2 h
\]

Where:
- \( r \) is the radius (18 ft)
- \( h \) is the height (11 ft)

### Step 1: Plug the values into the formula
\[
V = \frac{1}{3} \pi (18)^2 (11)
\]

\[
V = \frac{1}{3} \pi (324) (11)
\]

\[
V = \frac{1}{3} \pi (3564)
\]

\[
V = 1188 \pi \, \text{ft}^3
\]

### Step 2: Approximate value
Using \( \pi \approx 3.1416 \):

\[
V \approx 1188 \times 3.1416 = 3732.59 \, \text{ft}^3
\]

### Final answer:
- Exact value: \( 1188 \pi \, \text{ft}^3 \)
- Approximation: \( 3732.59 \, \text{ft}^3 \)

Would you like more details on how these calculations were performed, or do you have any other questions?

Here are 5 related questions you can explore:
1. How would the volume change if the height of the cone were doubled?
2. What is the surface area of this cone?
3. How does the formula for the volume of a cone compare with that of a cylinder?
4. What is the effect on volume if both the radius and the height are doubled?
5. How would you calculate the slant height of this cone?

**Tip**: Always use the exact form (in terms of π) when possible, especially for problems requiring precision, to avoid rounding errors.

Find the volume of a cone with a radius of 18 feet and a height of 11 feet. Provide both the exact value in terms of π and an approximation to the nearest hundredth.

This page explains how to calculate the volume of a cone with a radius of 18 feet and a height of 11 feet. Learn the exact value in terms of π and the approximate volume rounded to the nearest hundredth. Suitable for students in Grades 8-10.

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