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To solve this problem, we need to calculate the volume of a composite shape consisting of a cylinder with two hemispheres attached at each end.

### Step-by-Step Solution

1. **Volume of the Cylinder:**
   - The cylinder has a height \( h = 2 \) meters and a radius \( r = 3 \) meters.
   - The formula for the volume of a cylinder is:
     \[
     V_{\text{cylinder}} = \pi r^2 h
     \]
   - Substituting the values:
     \[
     V_{\text{cylinder}} = \pi \times 3^2 \times 2 = 18\pi \approx 56.5 \text{ m}^3
     \]

2. **Volume of the Hemispheres:**
   - The shape includes two hemispheres with a radius \( r = 3 \) meters.
   - The volume of a full sphere is:
     \[
     V_{\text{sphere}} = \frac{4}{3} \pi r^3
     \]
   - Since we have two hemispheres, their combined volume is equal to the volume of a full sphere:
     \[
     V_{\text{hemispheres}} = \frac{4}{3} \pi \times 3^3 = 36\pi \approx 113.1 \text{ m}^3
     \]

3. **Total Volume:**
   - Adding the volumes of the cylinder and the hemispheres:
     \[
     V_{\text{total}} = V_{\text{cylinder}} + V_{\text{hemispheres}} = 18\pi + 36\pi = 54\pi \approx 169.6 \text{ m}^3
     \]

### Final Answer
The volume of the composite shape is approximately **169.6 m³**.

Would you like further details or have any questions?

Here are some related questions for further practice:
1. How would the volume change if the radius of the cylinder and hemispheres were doubled?
2. How do you calculate the surface area of a similar composite shape?
3. What is the effect on volume if the height of the cylinder is tripled?
4. How would you find the volume if only one hemisphere is attached to the cylinder?
5. Can this shape be divided in any other ways for easier calculations?

**Tip:** When working with composite shapes, break down the shape into simpler parts and solve each part separately before summing the volumes.

Calculate the volume of the following composite shape. Give your answer to one decimal place.

Learn how to calculate the volume of a composite shape consisting of a cylinder and two hemispheres. This problem involves geometry concepts and volume formulas, perfect for students in Grades 8-10. The solution provides a detailed, step-by-step approach with the final answer rounded to one decimal place.

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