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Let's go through each of the problems step-by-step.

### Problem 1: How long will the ball be in the air before it strikes the floor?

We are given:
- Initial velocity \( v_0 = 6.0 \, \text{m/s} \) (upward)
- Initial height \( y_0 = 2.0 \, \text{m} \)
- Acceleration due to gravity \( a = -9.8 \, \text{m/s}^2 \)

We need to find the total time the ball is in the air. This requires finding the time to reach maximum height and then the time to fall back down to the floor.

1. **Find the velocity at the point of impact with the floor**:
    - The velocity can be found using the kinematic equation:
      \[
      v^2 = v_0^2 + 2a(y - y_0)
      \]
      where \( y = 0 \) (the floor).

2. **Using this equation, solve for time**:
    - Once we find the velocity at the point of impact, we can use \( v = v_0 + at \) to find the time.

### Problem 2: What is the highest point above the ground the ball will reach?

Here, we are asked to find the maximum height:
- The velocity at the highest point will be \( v = 0 \).
- Using the kinematic equation:
  \[
  v^2 = v_0^2 + 2a(y - y_0)
  \]
  we can solve for \( y \), where \( y_0 = 2.0 \, \text{m} \), \( v_0 = 6.0 \, \text{m/s} \), and \( a = -9.8 \, \text{m/s}^2 \).

### Problem 3: How high will the second volleyball go?

We are given:
- Initial velocity \( v_0 = 7.5 \, \text{m/s} \)
- Initial height \( y_0 = 0.80 \, \text{m} \)
- Acceleration due to gravity \( a = -9.8 \, \text{m/s}^2 \)

To find the maximum height, we use the same kinematic equation:
\[
v^2 = v_0^2 + 2a(y - y_0)
\]
with \( v = 0 \) at the highest point.

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I will calculate and provide the detailed solutions now.

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A volleyball is hit straight up into the air with an initial velocity of 6.0 m/s. How long will it be in the air before it strikes the floor? Also, what is the highest point it will reach?

Learn how to calculate the total time a volleyball remains in the air and the highest point it reaches using kinematic equations. Includes step-by-step solutions for motion problems with initial velocity and gravity.

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