Math Problem Statement

Let 𝑀𝑀(π‘₯π‘₯) = βˆ’ 2 5 |π‘₯π‘₯ + 3| + 2 restricted over {π‘₯π‘₯ β‰₯ β„Ž} where (β„Ž, π‘˜π‘˜) are the coordinates of the vertex. What is the vertex of 𝑀𝑀 βˆ’1(π‘₯π‘₯)? A. (βˆ’3, 2) B. (3, βˆ’2) C. (βˆ’2, 3) D. (2, βˆ’3)

Solution

To find the vertex of wβˆ’1(x)w^{-1}(x), we first need to determine the vertex of the original function w(x)=βˆ’25∣x+3∣+2w(x) = -\frac{2}{5} |x + 3| + 2.

Step 1: Identify the vertex of the original function w(x)w(x)

The function is in the form of w(x)=a∣xβˆ’h∣+kw(x) = a|x - h| + k, where the vertex is at the point (h,k)(h, k).

In this case:

  • a=βˆ’25a = -\frac{2}{5}
  • ∣x+3∣|x + 3| means the vertex is at x=βˆ’3x = -3 (opposite sign inside the absolute value).
  • k=2k = 2

Thus, the vertex of w(x)w(x) is (βˆ’3,2)(-3, 2).

Step 2: Find the vertex of the inverse function wβˆ’1(x)w^{-1}(x)

For the inverse function wβˆ’1(x)w^{-1}(x), the vertex will be the reverse of the vertex coordinates of w(x)w(x). Therefore, the vertex of wβˆ’1(x)w^{-1}(x) is (2,βˆ’3)(2, -3).

Final Answer:

The vertex of wβˆ’1(x)w^{-1}(x) is (2,βˆ’3)\boxed{(2, -3)}, which corresponds to option D.


Would you like more details on any part of the process? Here are 5 related questions to deepen your understanding:

  1. How do we find the inverse of an absolute value function like w(x)w(x)?
  2. Why does the vertex of the inverse function swap the coordinates?
  3. Can the graph of w(x)w(x) help visualize the inverse function?
  4. What is the significance of the sign of aa in determining the function's shape?
  5. How can transformations like shifting and stretching affect the vertex?

Tip: When dealing with inverse functions, remember that the roles of xx and yy are reversed.

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Math Problem Analysis

Mathematical Concepts

Inverse Functions
Absolute Value Functions
Vertex Form

Formulas

w(x) = a|x - h| + k
Inverse of a function swaps x and y coordinates

Theorems

Inverse Function Theorem

Suitable Grade Level

Grades 10-12