Titik L(1, 5) pada ellips (x-3)2(y+4)2 + = 1

It seems like you're working with an ellipse equation, but the equation you provided is incomplete. Let me clarify the typical form of the equation of an ellipse:

An ellipse is generally given by:

\[
\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1
\]

Where:
- \((h, k)\) is the center of the ellipse,
- \(a\) is the semi-major axis (horizontal distance from the center),
- \(b\) is the semi-minor axis (vertical distance from the center).

The point \(L(1, 5)\) would be a point you need to check if it lies on the ellipse by substituting into the correct equation.

Could you confirm or complete the equation? I noticed it starts with \((x-3)^2\), but it seems part of it is missing. I can help once the full equation is clear.

Would you like more details about ellipses or solving related problems?

Here are 5 relative questions to think about:
1. What are the values of \(a\) and \(b\) in your ellipse equation?
2. How do you check if a point lies on an ellipse?
3. Can you describe the significance of the center of an ellipse in relation to its equation?
4. Do you know the difference between the major and minor axes of an ellipse?
5. How do you find the foci of an ellipse?

**Tip:** The sum of distances from any point on an ellipse to its two foci is always constant!

Learn how to verify if point L(1, 5) lies on an ellipse with the equation (x-3)^2/a^2 + (y+4)^2/b^2 = 1. This problem explores the geometry of ellipses, focusing on key concepts like conic sections, substitution, and ellipse properties. Suitable for students in Grades 10-12.

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