Math Problem Statement

Water flows from a reservoir into a closed tank in which the pressure is 70kN/m² below the atmospheric. If the water level in the reservoir is 6m above that in the tank, find the velocity of water entering the tank, neglecting friction.

What formula should I use to solve this question

Solution

To solve this question, you can apply Bernoulli's equation to relate the energy (pressure, velocity, and height) of the water at different points. Since you're given the height difference between the reservoir and the tank, and the pressure difference between the two, Bernoulli’s principle is appropriate to find the velocity of water entering the tank.

Step-by-Step Approach:

Bernoulli's equation states:

P1ρg+v122g+z1=P2ρg+v222g+z2\frac{P_1}{\rho g} + \frac{v_1^2}{2g} + z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} + z_2

Where:

  • P1P_1, P2P_2 = pressures at points 1 (reservoir) and 2 (tank),
  • v1v_1, v2v_2 = velocities at points 1 and 2,
  • z1z_1, z2z_2 = elevations at points 1 and 2,
  • ρ\rho = density of water,
  • gg = acceleration due to gravity.

Assumptions for your case:

  1. Reservoir (Point 1): The water is at rest, so v1=0v_1 = 0.
  2. Tank (Point 2): The velocity of the water entering the tank is v2v_2, which we need to find.
  3. The pressure at the tank is P2=70kN/m2P_2 = -70 \, \text{kN/m}^2, which is below atmospheric pressure.
  4. The height difference is z1z2=6mz_1 - z_2 = 6 \, \text{m}.

The simplified equation:

Using Bernoulli's equation between the reservoir and the tank:

P1ρg+z1=P2ρg+v222g+z2\frac{P_1}{\rho g} + z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} + z_2

Since the water is flowing freely, you can neglect P1P_1 because it's a reference point, and assume the velocity at the reservoir is zero. The equation reduces to:

P2ρg+z2=v222g+z1\frac{P_2}{\rho g} + z_2 = \frac{v_2^2}{2g} + z_1

Solving for v2v_2:

v222g=z1z2+P2ρg\frac{v_2^2}{2g} = z_1 - z_2 + \frac{P_2}{\rho g}

v2=2g(z1z2+P2ρg)v_2 = \sqrt{2g \left( z_1 - z_2 + \frac{P_2}{\rho g} \right)}

This formula will allow you to compute the velocity of water entering the tank.

Parameters:

  • g9.81m/s2g \approx 9.81 \, \text{m/s}^2 (acceleration due to gravity),
  • P2=70kN/m2=70,000N/m2P_2 = -70 \, \text{kN/m}^2 = -70,000 \, \text{N/m}^2 (pressure below atmospheric),
  • ρ=1000kg/m3\rho = 1000 \, \text{kg/m}^3 (density of water),
  • z1z2=6mz_1 - z_2 = 6 \, \text{m} (height difference).

Would you like me to calculate the velocity using this formula, or would you like more details on how to proceed?

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Math Problem Analysis

Mathematical Concepts

Fluid Dynamics
Bernoulli's Equation
Kinematics of Fluids

Formulas

Bernoulli's equation: P1/ρg + v1^2/2g + z1 = P2/ρg + v2^2/2g + z2
Velocity formula: v2 = √(2g * (z1 - z2 + P2/ρg))

Theorems

Bernoulli's Principle

Suitable Grade Level

Grades 11-12