Math Problem Statement

Compute the monthly payment and the total amount spent for a vehicle that costs ​$22 comma 700 if you finance the entire purchase over 5 years at an annual rate of 8.25 percent. Calculate the payment if you finance the car for only four years.​ Finally, calculate the payment for three years. What do you notice about the payment under the different time​ assumptions?   ​Note: Round intermediate computations to at least five​ (5) decimal places.

Solution

To solve this, we will use the formula for the monthly payment on an amortized loan:

M=Pr(1+r)n(1+r)n1M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n - 1}

Where:

  • MM is the monthly payment.
  • PP is the loan principal (the amount financed, which is $22,700).
  • rr is the monthly interest rate (annual interest rate divided by 12).
  • nn is the number of monthly payments (loan term in months).

Step 1: Calculate Monthly Payment for 5 Years

  1. Principal (P): $22,700
  2. Annual Interest Rate (APR): 8.25%
    • Monthly Interest Rate r=8.25%12=0.006875r = \frac{8.25\%}{12} = 0.006875
  3. Loan Term (n): 5 years = 5 × 12 = 60 months

Now, applying the formula:

M=227000.006875(1+0.006875)60(1+0.006875)601M = \frac{22700 \cdot 0.006875 \cdot (1 + 0.006875)^{60}}{(1 + 0.006875)^{60} - 1}

Calculating this gives:

M463.81M \approx 463.81

Step 2: Total Amount Spent for 5 Years

Total spent is:

Total=M×n=463.81×60=27,828.60\text{Total} = M \times n = 463.81 \times 60 = 27,828.60

Step 3: Calculate Monthly Payment for 4 Years

  1. Loan Term (n): 4 years = 4 × 12 = 48 months

Now, using the same formula but with n=48n = 48:

M=227000.006875(1+0.006875)48(1+0.006875)481M = \frac{22700 \cdot 0.006875 \cdot (1 + 0.006875)^{48}}{(1 + 0.006875)^{48} - 1}

Calculating this gives:

M555.72M \approx 555.72

Step 4: Total Amount Spent for 4 Years

Total spent is:

Total=M×n=555.72×48=26,674.56\text{Total} = M \times n = 555.72 \times 48 = 26,674.56

Step 5: Calculate Monthly Payment for 3 Years

  1. Loan Term (n): 3 years = 3 × 12 = 36 months

Now, using the same formula but with n=36n = 36:

M=227000.006875(1+0.006875)36(1+0.006875)361M = \frac{22700 \cdot 0.006875 \cdot (1 + 0.006875)^{36}}{(1 + 0.006875)^{36} - 1}

Calculating this gives:

M713.83M \approx 713.83

Step 6: Total Amount Spent for 3 Years

Total spent is:

Total=M×n=713.83×36=25,297.88\text{Total} = M \times n = 713.83 \times 36 = 25,297.88

Summary of Results

  1. 5 years:
    • Monthly payment: $463.81
    • Total spent: $27,828.60
  2. 4 years:
    • Monthly payment: $555.72
    • Total spent: $26,674.56
  3. 3 years:
    • Monthly payment: $713.83
    • Total spent: $25,297.88

Observation:

As the loan term shortens, the monthly payment increases, but the total amount spent decreases. This is because a shorter term means less time for interest to accrue.


Would you like more details on any part of this calculation or have any questions?

Here are 5 related questions for further practice:

  1. How would the payment change if the interest rate were reduced to 6%?
  2. What is the total interest paid over 5 years?
  3. How much would you save in total interest by financing over 3 years instead of 5 years?
  4. How would the monthly payment change if a $5,000 down payment were made?
  5. What is the impact of compounding interest on monthly payments over time?

Tip: Shorter loan terms reduce the total amount of interest paid but increase the monthly payment.

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Math Problem Analysis

Mathematical Concepts

Loan Amortization
Interest Rates
Finance

Formulas

M = (P * r * (1 + r)^n) / ((1 + r)^n - 1)
Total Spent = M * n

Theorems

Loan Amortization Formula

Suitable Grade Level

College Finance or High School Advanced Math