Math Problem Statement

Parmi les énoncés suivants le ou lesquels est/sont vrais? (Includes vector spaces, subspaces, and linear dependence)

Solution

The image shows a mathematical question asking which of the given statements are true or false. The problem is about vector spaces, subspaces, and linear independence in various mathematical contexts. Here's a breakdown of each statement and the correctness (in blue) marked in the image:

Statement Breakdown:

  1. Statement I: "The set of vectors {(1,2),(2,1),(0,1)}\{(1,2), (2,1), (0,1)\} spans R2\mathbb{R}^2."
    Marked as True (Vrai): This is correct. These three vectors are linearly independent and span R2\mathbb{R}^2, so the set generates R2\mathbb{R}^2.

  2. Statement II: "The set {(x,y,z)xy+2z=1}\{(x, y, z) \mid x - y + 2z = -1\} is a subspace of R3\mathbb{R}^3."
    Marked as False (Faux): This is correct. A subspace of R3\mathbb{R}^3 must contain the zero vector, but this equation does not pass through the origin (since for x=y=z=0x = y = z = 0, the equation gives 1-1), so it is not a subspace.

  3. Statement III: "In a vector space VV, if there exists a vector that is a linear combination of uvu - v and u+wu + w, then the vectors {u,v,w}\{u, v, w\} span VV."
    Marked as False (Faux): This is correct. The linear combination condition provided does not necessarily imply that {u,v,w}\{u, v, w\} will span the space VV, as more specific conditions are needed for this.

  4. Statement IV: "The set {p(x)P2p(1)=0}\{p(x) \in \mathbb{P}_2 \mid p(-1) = 0\} is a subspace of P2\mathbb{P}_2, where P2\mathbb{P}_2 is the space of polynomials of degree at most 2."
    Marked as True (Vrai): This is correct. The condition p(1)=0p(-1) = 0 is a homogeneous condition, and the set of such polynomials forms a subspace of P2\mathbb{P}_2.

  5. Statement V: "The set {cos2(3x),sin2(3x),2}\{\cos^2(3x), \sin^2(3x), 2\} is linearly dependent in F(R)\mathcal{F}(\mathbb{R}), where F(R)\mathcal{F}(\mathbb{R}) is the space of functions defined on R\mathbb{R}."
    Marked as True (Vrai): This is correct. The trigonometric identity cos2(3x)+sin2(3x)=1\cos^2(3x) + \sin^2(3x) = 1 shows that these functions are linearly dependent.

Would you like further details or explanations on any of these topics?

Five Related Questions:

  1. What are the conditions for a set of vectors to span a vector space?
  2. How do you verify if a set of functions is linearly dependent?
  3. What is the significance of the zero vector in determining if a set is a subspace?
  4. Can you explain why the condition p(1)=0p(-1) = 0 ensures a subspace of P2\mathbb{P}_2?
  5. How do trigonometric identities help in establishing linear dependence of functions?

Tip:

When checking whether a set is a subspace, always verify that it contains the zero vector and is closed under addition and scalar multiplication.

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Math Problem Analysis

Mathematical Concepts

Vector Spaces
Subspaces
Linear Independence
Polynomial Spaces
Function Spaces

Formulas

Subspace condition: Contains zero vector, closed under addition and scalar multiplication
Trigonometric Identity: cos²(x) + sin²(x) = 1

Theorems

Linear Independence Theorem
Subspace Theorem
Polynomial Subspaces in P2

Suitable Grade Level

Undergraduate Mathematics