Math Problem Statement

Given the vector uu equal to 8, open angle bracket, cosine, 105, degrees, comma, sine, 105, degrees, close angle bracket8⟨cos105 ∘ ,sin105 ∘ ⟩ and vector vv equal to 4, open angle bracket, cosine, 205, degrees, comma, sine, 205, degrees, close angle bracket, comma4⟨cos205 ∘ ,sin205 ∘ ⟩, find the sum u, plus, vu+v and write your answer in magnitude and direction form with the magnitude rounded to the nearest tenth and the direction rounded to the nearest degree,

Solution

To find the sum of the vectors u and v and then express it in magnitude and direction form, follow these steps:

Step 1: Determine the components of the vectors u and v

Given:

  • u=8cos105,sin105\mathbf{u} = 8 \langle \cos 105^\circ, \sin 105^\circ \rangle
  • v=4cos205,sin205\mathbf{v} = 4 \langle \cos 205^\circ, \sin 205^\circ \rangle

We can calculate the components:

ux=8cos105,uy=8sin105\mathbf{u}_x = 8 \cos 105^\circ, \quad \mathbf{u}_y = 8 \sin 105^\circ

vx=4cos205,vy=4sin205\mathbf{v}_x = 4 \cos 205^\circ, \quad \mathbf{v}_y = 4 \sin 205^\circ

Step 2: Calculate the components

Using a calculator for the trigonometric functions:

cos1050.2588,sin1050.9659\cos 105^\circ \approx -0.2588, \quad \sin 105^\circ \approx 0.9659 cos2050.9063,sin2050.4226\cos 205^\circ \approx -0.9063, \quad \sin 205^\circ \approx -0.4226

Now, compute the components:

ux=8×(0.2588)2.0704,uy=8×0.96597.7272\mathbf{u}_x = 8 \times (-0.2588) \approx -2.0704, \quad \mathbf{u}_y = 8 \times 0.9659 \approx 7.7272

vx=4×(0.9063)3.6252,vy=4×(0.4226)1.6904\mathbf{v}_x = 4 \times (-0.9063) \approx -3.6252, \quad \mathbf{v}_y = 4 \times (-0.4226) \approx -1.6904

Step 3: Find the sum of the vectors

Add the corresponding components of u\mathbf{u} and v\mathbf{v}:

u+v=ux+vx,uy+vy\mathbf{u} + \mathbf{v} = \langle \mathbf{u}_x + \mathbf{v}_x, \mathbf{u}_y + \mathbf{v}_y \rangle

u+v=2.07043.6252,7.72721.6904\mathbf{u} + \mathbf{v} = \langle -2.0704 - 3.6252, 7.7272 - 1.6904 \rangle

u+v5.6956,6.0368\mathbf{u} + \mathbf{v} \approx \langle -5.6956, 6.0368 \rangle

Step 4: Calculate the magnitude of the resultant vector

The magnitude u+v\|\mathbf{u} + \mathbf{v}\| is given by:

u+v=(5.6956)2+(6.0368)2\|\mathbf{u} + \mathbf{v}\| = \sqrt{(-5.6956)^2 + (6.0368)^2}

u+v32.4293+36.443068.87238.3\|\mathbf{u} + \mathbf{v}\| \approx \sqrt{32.4293 + 36.4430} \approx \sqrt{68.8723} \approx 8.3

Step 5: Determine the direction (angle) of the resultant vector

The direction θ\theta (relative to the positive x-axis) is given by:

θ=tan1(uy+vyux+vx)\theta = \tan^{-1}\left(\frac{\mathbf{u}_y + \mathbf{v}_y}{\mathbf{u}_x + \mathbf{v}_x}\right)

θ=tan1(6.03685.6956)\theta = \tan^{-1}\left(\frac{6.0368}{-5.6956}\right)

θtan1(1.060)46.5\theta \approx \tan^{-1}(-1.060) \approx -46.5^\circ

Since the resultant vector is in the second quadrant (negative x-component and positive y-component), the direction angle should be adjusted:

θ18046.5134\theta \approx 180^\circ - 46.5^\circ \approx 134^\circ

Final Answer:

  • Magnitude: 8.38.3 (rounded to the nearest tenth)
  • Direction: 134134^\circ (rounded to the nearest degree)

Would you like to explore further details or have any questions?

Related Questions:

  1. How do you calculate the dot product of two vectors?
  2. What is the significance of the angle between two vectors in vector operations?
  3. Can you explain how to find the vector projection of one vector onto another?
  4. How can vector cross products be applied in physics?
  5. What are some practical applications of vector addition in engineering?

Tip:

When adding vectors graphically, always remember to consider the direction (angle) and magnitude to ensure accurate results.

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Math Problem Analysis

Mathematical Concepts

Vector Addition
Trigonometry
Magnitude and Direction of Vectors

Formulas

Magnitude of a Vector
Direction (Angle) of a Vector

Theorems

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Suitable Grade Level

Advanced High School / College Level