Math Problem Statement

Дисперсия случайной величины X = 3. Найдите дисперсию случайной величины Y, если Y = -5X - 1.

Solution

The problem states:

  1. The variance of the random variable XX is given as Var(X)=3\text{Var}(X) = 3.
  2. The relationship between YY and XX is Y=5X1Y = -5X - 1.

Solution:

The variance of a transformed random variable YY is computed using the formula:

Var(Y)=a2Var(X),\text{Var}(Y) = a^2 \cdot \text{Var}(X),

where Y=aX+bY = aX + b, and:

  • aa is the coefficient of XX,
  • bb is a constant (does not affect the variance).

From Y=5X1Y = -5X - 1, we identify a=5a = -5 and b=1b = -1. Substituting into the formula:

Var(Y)=(5)2Var(X)=253=75.\text{Var}(Y) = (-5)^2 \cdot \text{Var}(X) = 25 \cdot 3 = 75.

Final Answer:

Var(Y)=75\text{Var}(Y) = 75

Would you like further clarification or a more detailed breakdown?


Related Questions:

  1. How does adding a constant bb to a random variable affect its variance?
  2. Can you explain the general formula for the variance of a linear transformation of random variables?
  3. What is the significance of variance in probability and statistics?
  4. How would the calculation change if Y=5X+1Y = 5X + 1?
  5. If XX has a standard deviation of 3\sqrt{3}, what is the standard deviation of YY?

Tip:

Always remember that the variance depends on the square of the scaling factor but is unaffected by added constants.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Variance
Random Variables
Linear Transformations

Formulas

Var(Y) = a^2 * Var(X)
Y = aX + b

Theorems

Variance scaling property

Suitable Grade Level

Undergraduate or Advanced High School (Grades 10-12)