Math Problem Statement

Suppose the utility function for Njeru is given by U = X1^0.25 * X2^0.75. Given that the price of commodity X1 is Kshs. 5 per unit and that of commodity X2 is Kshs. 10 per unit, and given an income of Kshs. 30,000, use the Lagrangian multiplier technique to determine units of the two commodities Njeru will buy in order to maximize his utility.

Solution

The question involves solving a utility maximization problem using the Lagrangian multiplier technique.

Solution for Part (a):

The utility function is given by: U(X1,X2)=X10.25X20.75U(X_1, X_2) = X_1^{0.25} X_2^{0.75}

Prices of commodities: PX1=5Ksh/unit,PX2=10Ksh/unitP_{X_1} = 5 \, \text{Ksh/unit}, \, P_{X_2} = 10 \, \text{Ksh/unit}

Income: I=30,000KshI = 30,000 \, \text{Ksh}

Steps to Maximize Utility:

  1. Budget Constraint: PX1X1+PX2X2=IP_{X_1} X_1 + P_{X_2} X_2 = I Substituting values: 5X1+10X2=30,0005X_1 + 10X_2 = 30,000

  2. Lagrangian Function: L=X10.25X20.75+λ(30,0005X110X2)\mathcal{L} = X_1^{0.25} X_2^{0.75} + \lambda (30,000 - 5X_1 - 10X_2)

  3. Partial Derivatives: Take partial derivatives w.r.t X1X_1, X2X_2, and λ\lambda: LX1=0.25X10.75X20.755λ=0\frac{\partial \mathcal{L}}{\partial X_1} = 0.25X_1^{-0.75} X_2^{0.75} - 5\lambda = 0 LX2=0.75X10.25X20.2510λ=0\frac{\partial \mathcal{L}}{\partial X_2} = 0.75X_1^{0.25} X_2^{-0.25} - 10\lambda = 0 Lλ=30,0005X110X2=0\frac{\partial \mathcal{L}}{\partial \lambda} = 30,000 - 5X_1 - 10X_2 = 0

  4. Solving the Equations:

    • From the first two equations: 0.25X10.75X20.755=0.75X10.25X20.2510\frac{0.25X_1^{-0.75} X_2^{0.75}}{5} = \frac{0.75X_1^{0.25} X_2^{-0.25}}{10} Simplify: X2X1=1.5\frac{X_2}{X_1} = 1.5 Hence: X2=1.5X1X_2 = 1.5X_1

    • Substitute X2=1.5X1X_2 = 1.5X_1 into the budget constraint: 5X1+10(1.5X1)=30,0005X_1 + 10(1.5X_1) = 30,000 5X1+15X1=30,0005X_1 + 15X_1 = 30,000 20X1=30,000    X1=1,50020X_1 = 30,000 \implies X_1 = 1,500

    • Calculate X2X_2: X2=1.5×1,500=2,250X_2 = 1.5 \times 1,500 = 2,250

Final Results:

  • Optimal quantities: X1=1,500,X2=2,250X_1 = 1,500, \, X_2 = 2,250

Explanation for Part (b):

Using a table, describe and explain practical applications of the Cardinal Utility Approach. This involves scenarios like consumer decision-making under budget constraints, pricing strategies, and market analysis.

Would you like detailed explanations for part (b) or more elaboration on the mathematical derivations?


Related Questions:

  1. What is the significance of the Lagrangian multiplier in this context?
  2. How would the solution change if the income were doubled?
  3. Can you derive the marginal rate of substitution (MRS) at the optimal point?
  4. What are the practical implications of this optimization problem in market economics?
  5. How does the elasticity of substitution between X1X_1 and X2X_2 influence the utility maximization?

Tip:

Always check the validity of your solutions by verifying they satisfy both the utility function and the budget

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Math Problem Analysis

Mathematical Concepts

Utility Maximization
Lagrangian Multiplier
Budget Constraint

Formulas

Lagrangian Function: L = U(X1, X2) + λ (Income - P1X1 - P2X2)
Partial Derivatives for optimization: ∂L/∂X1 = 0, ∂L/∂X2 = 0, ∂L/∂λ = 0
Budget Constraint: P1X1 + P2X2 = Income

Theorems

Lagrange Multiplier Theorem

Suitable Grade Level

Undergraduate (Economics/Mathematics)