Math Problem Statement

1. A basketball coach insists that his players be at least 6 ft tall. Would a player with a height of 180 cm qualify for the team? 2. A football field is 100.0 yards long. Express this distance in meters. 3. A car is traveling at a speed of 33 m/s. Is it exceeding the 65 mph speed limit? 4. From a horizontal distance of 80.0 m, the angle of elevation to the top of a flagpole is 18°. Calculate the height of the flagpole to the nearest tenth of a meter. 5. A wheelchair ramp is 4.2 m long. It rises 0.7 m. What is its angle of inclination to the nearest degree?

Solution

Let's go through each of the questions in the image step by step:

  1. Basketball Player Height Qualification
    The coach requires players to be at least 6 ft tall.
    Conversion from centimeters to feet:
    1ft=30.48cm1 \, \text{ft} = 30.48 \, \text{cm}
    So, the player's height in feet is: 180cm30.48=5.91ft\frac{180 \, \text{cm}}{30.48} = 5.91 \, \text{ft} Since 5.91 ft is less than 6 ft, the player does not qualify.

  2. Converting Yards to Meters
    A football field is 100 yards long.
    Conversion factor:
    1yard=0.9144meters1 \, \text{yard} = 0.9144 \, \text{meters}
    Therefore: 100yards×0.9144=91.44meters100 \, \text{yards} \times 0.9144 = 91.44 \, \text{meters}

  3. Speed Conversion: 33 m/s to mph
    The speed of the car is 33 m/s. To determine if it exceeds 65 mph, we first convert m/s to mph:
    1m/s=2.23694mph1 \, \text{m/s} = 2.23694 \, \text{mph}
    Therefore: 33m/s×2.23694=73.82mph33 \, \text{m/s} \times 2.23694 = 73.82 \, \text{mph} Since 73.82 mph is greater than 65 mph, the car is exceeding the speed limit.

  4. Calculating Flagpole Height using Trigonometry
    We know:

    • Distance from flagpole (adjacent) = 80 m
    • Angle of elevation = 18°

    Using the tangent function:
    tan(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
    Thus, the height of the flagpole is: Height=80×tan(18)26m\text{Height} = 80 \times \tan(18^\circ) \approx 26 \, \text{m}

  5. Calculating Angle of Inclination for Wheelchair Ramp
    We know:

    • Ramp length (hypotenuse) = 4.2 m
    • Height (opposite) = 0.7 m

    Using the sine function:
    sin(θ)=oppositehypotenuse=0.74.2\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{0.7}{4.2}
    Solving for the angle θ\theta: θ=sin1(0.74.2)10\theta = \sin^{-1}\left(\frac{0.7}{4.2}\right) \approx 10^\circ

Would you like further details or have any questions?

Here are some related questions to explore:

  1. What would the minimum height in cm be to qualify for a basketball team that requires players to be at least 6 ft tall?
  2. How many meters are there in a 120-yard-long football field?
  3. What speed in m/s is equivalent to 70 mph?
  4. If the angle of elevation to a flagpole were 25°, what would its height be from the same distance?
  5. How long would a wheelchair ramp need to be if it rises 1 m at the same angle?

Tip: When solving trigonometric problems, always double-check that your calculator is set to the correct unit (degrees or radians) based on the problem.

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Math Problem Analysis

Mathematical Concepts

Unit Conversion
Trigonometry
Speed Conversion
Geometry

Formulas

1 ft = 30.48 cm
1 yard = 0.9144 m
1 m/s = 2.23694 mph
tan(θ) = opposite / adjacent
sin(θ) = opposite / hypotenuse

Theorems

Pythagorean Theorem
Tangent Function
Sine Function

Suitable Grade Level

Grades 9-12