Perform the indicated operation. Express your final answer to the correct number of significant figures 992mL - 100.35c * m ^ 3 - 0.468L

To solve the expression \( 992 \, \text{mL} - 100.35 \, \text{cm}^3 - 0.468 \, \text{L} \), let's first ensure all units are the same. We can convert everything to milliliters (mL) since that's the initial unit given:

1. **Conversion from cubic centimeters to milliliters**:
   \[
   100.35 \, \text{cm}^3 = 100.35 \, \text{mL} \quad \text{(since } 1 \, \text{cm}^3 = 1 \, \text{mL} \text{)}
   \]

2. **Conversion from liters to milliliters**:
   \[
   0.468 \, \text{L} = 0.468 \times 1000 \, \text{mL} = 468 \, \text{mL}
   \]

Now, we can perform the subtraction:

\[
992 \, \text{mL} - 100.35 \, \text{mL} - 468 \, \text{mL}
\]

\[
= (992 - 100.35 - 468) \, \text{mL}
\]

\[
= 423.65 \, \text{mL}
\]

Finally, we need to express the final answer to the correct number of significant figures. The original numbers had the following significant figures:

- \( 992 \, \text{mL} \) has 3 significant figures.
- \( 100.35 \, \text{cm}^3 \) has 5 significant figures.
- \( 0.468 \, \text{L} \) has 3 significant figures.

The result should be expressed to 3 significant figures, the least number in the given values:

\[
423.65 \, \text{mL} \approx 424 \, \text{mL}
\]

**Final Answer:** \( 424 \, \text{mL} \).

Would you like more details or have any other questions?

Here are 5 related questions:

1. How do you convert between different units of volume?
2. What are significant figures, and why are they important?
3. How do you round numbers to a specific number of significant figures?
4. What is the difference between precision and accuracy in measurements?
5. Can you solve another problem involving unit conversion and significant figures?

**Tip:** Always ensure consistency in units before performing any mathematical operations to avoid errors in calculations.

Learn how to perform unit conversion and calculate the correct number of significant figures in the expression 992mL - 100.35cm³ - 0.468L. This problem is suitable for students in Grades 9-10 and involves converting between milliliters, cubic centimeters, and liters, ensuring precision in measurements.

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