Math Problem Statement

Can you explain the process for this, along with a practice problem

Can you explain the process for this, along with a practice problem

Solution

Let's walk through the problem:

Part a: Find the zeros and state their multiplicity

The graph shows the polynomial crossing or touching the x-axis at three points. These points are the zeros of the polynomial.

  1. The zero at x = -1 touches the x-axis but does not cross it. This indicates that the multiplicity of the zero is even (in this case, 2). Hence, x=1x = -1 has multiplicity 2.

  2. The zero at x = 1 crosses the x-axis, which means it has an odd multiplicity (specifically 1).

  3. The zero at x = 2 also crosses the x-axis, but the graph behaves in a way that shows a higher odd multiplicity (specifically 3).

  • Therefore, the zeros are:
    • x=1x = -1 with multiplicity 2 (even)
    • x=1x = 1 with multiplicity 1 (odd)
    • x=2x = 2 with multiplicity 3 (odd)

Part b: Write an equation for the polynomial

We need to write the polynomial as a product of factors. Each factor corresponds to a zero, and the multiplicity is the exponent on the factor.

  • For x=1x = -1, with multiplicity 2, the factor is (x+1)2(x + 1)^2.
  • For x=1x = 1, with multiplicity 1, the factor is (x1)1(x - 1)^1.
  • For x=2x = 2, with multiplicity 3, the factor is (x2)3(x - 2)^3.

The polynomial equation, with a leading coefficient of either 1 or -1, becomes:

f(x)=(x+1)2(x1)(x2)3f(x) = (x + 1)^2(x - 1)(x - 2)^3

Part c: Find the y-intercept

To find the y-intercept, substitute x=0x = 0 into the equation from part (b):

f(0)=(0+1)2(01)(02)3=(1)2(1)(2)3=1×1×(8)=8f(0) = (0 + 1)^2(0 - 1)(0 - 2)^3 = (1)^2(-1)(-2)^3 = 1 \times -1 \times (-8) = 8

Thus, the y-intercept is 8.


Practice Problem:

Graph: Suppose a graph has the following behavior:

  • A zero at x=0x = 0 with multiplicity 2 (the graph touches the x-axis).
  • A zero at x=3x = 3 with multiplicity 1 (the graph crosses the x-axis).
  • A zero at x=2x = -2 with multiplicity 3 (the graph crosses the x-axis, but "flattens" out near this point).

Questions: a. Find the zeros and state their multiplicity.
b. Write an equation for the polynomial with a leading coefficient of 1.
c. Find the y-intercept.

Tip: Remember that the behavior of the graph at each zero can help determine its multiplicity. Zeros with even multiplicities cause the graph to touch the x-axis, while zeros with odd multiplicities cause it to cross the axis.


Do you have any questions or need more details? Here are some related questions for further practice:

  1. How do you determine the multiplicity of a zero from a graph?
  2. What is the effect of the leading coefficient on the graph's orientation?
  3. How does the multiplicity of a zero affect the graph's behavior near that zero?
  4. How can you determine the degree of a polynomial by analyzing its graph?
  5. What is the significance of the y-intercept in a polynomial function?

Tip: Practice substituting different values into the polynomial equation to see how it behaves at various points!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Polynomial Functions
Zeros of Functions
Multiplicity of Zeros
Y-Intercepts

Formulas

f(x) = (x + 1)^2(x - 1)(x - 2)^3

Theorems

Multiplicity and Zeros Theorem

Suitable Grade Level

Grades 10-12