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Let's go through this problem.

The line \( y = mx \) intersects the y-axis at the origin, point \((0, 0)\). This is because there is no constant term in the equation, so the line passes through the origin. 

Now, consider the line \( y = mx + 2 \). Here, the constant term \(+2\) indicates a vertical shift. Specifically, it shifts the entire line \(y = mx\) up by 2 units. This means that every point on the line \( y = mx \) is now 2 units higher on the y-axis in the line \( y = mx + 2 \).

### Answer
The correct answer is:
- **B. The line has been shifted up 2 units.**

Would you like a further breakdown or have any questions?

Here are some related questions:
1. What is the significance of the constant term in a linear equation like \( y = mx + c \)?
2. How does changing the slope \( m \) affect the graph of the line?
3. What would the graph of \( y = mx - 2 \) look like in relation to \( y = mx \)?
4. How can you determine the y-intercept of a line just by looking at its equation?
5. If the line were shifted left or right, what changes would occur in the equation?

**Tip:** In linear equations, the y-intercept represents the point where the line crosses the y-axis, and it directly reflects any vertical shift.

Gwen knows that the line y = mx will intersect the y-axis at the point (0, 0). What can she infer about the line y = mx + 2?

Explore how adding a constant to the equation y = mx affects the graph by shifting it vertically. This problem is designed for Grade 8 students to understand vertical shifts in linear equations, focusing on how the y-intercept changes.

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