Math Problem Statement

What kind of variation is represented in the questions, and how are proportional relationships solved in each case?

Solution

Let's go through each question on the page to understand and answer them:

Question 19

The equation given is 10=ab10 = \frac{a}{b}. This represents an inverse variation because as bb increases, aa must decrease to keep the ratio constant.

  • Answer: b. inverse

Question 20

The equation given is xy=12xy = 12. This also represents inverse variation since the product of xx and yy is constant. If xx increases, yy must decrease, and vice versa.

  • Answer: b. inverse

Question 21

The question asks for an equation where the volume VV varies directly with the temperature TT and inversely with the pressure PP. This translates to V=kTPV = \frac{kT}{P}.

  • Answer: a. V=kTPV = \frac{kT}{P}

Question 22

yy is inversely proportional to x2x^2. So, y=kx2y = \frac{k}{x^2}. Given y=49y = \frac{4}{9} when x=3x = -3:

  1. Find kk: 49=k(3)2k=4\frac{4}{9} = \frac{k}{(-3)^2} \Rightarrow k = 4.
  2. Now, when x=6x = -6: y=4(6)2=436=19y = \frac{4}{(-6)^2} = \frac{4}{36} = \frac{1}{9}.
  • Answer: d. 19\frac{1}{9}

Question 23

If mm is directly proportional to n2n^2, then m=kn2m = kn^2. If nn increases by 25%, nn becomes 1.25n1.25n:

  1. New mm becomes k(1.25n)2=k1.5625n2k(1.25n)^2 = k \cdot 1.5625 \cdot n^2.
  2. So mm increases by 56.25%.
  • Answer: c. mm increases by 56.25%

Question 24

If yy varies directly with xx, y=kxy = kx. Given x=10x = 10 when y=50y = 50:

  1. k=yx=5010=5k = \frac{y}{x} = \frac{50}{10} = 5.
  2. To find xx when y=60y = 60: 60=5xx=1260 = 5x \Rightarrow x = 12.
  • Answer: b. 12

Question 25

If VV is inversely proportional to XX and V=7V = 7 when X=2X = 2, then VX=kV \cdot X = k.

  1. k=7×2=14k = 7 \times 2 = 14.
  2. Let's analyze each statement:
    • I. True, as k=14k = 14.
    • II. False, as V=kXV = \frac{k}{X}, not V=kXV = kX.
    • III. True, if V=14V = 14, X=kV=1414=1X = \frac{k}{V} = \frac{14}{14} = 1.
    • IV. True, XX is inversely proportional to VV.
  • Answer: d. I, III, and IV

Question 26

The area AA of a circle is directly proportional to the square of its radius rr, which means A=kr2A = kr^2. Given A314A \approx 314 when r=10r = 10:

  1. k=Ar2=314102=3.14k = \frac{A}{r^2} = \frac{314}{10^2} = 3.14.
  • Answer: d. A=3.14r2A = 3.14r^2

Would you like detailed explanations for any of these answers?


Here are 5 questions that build on this material:

  1. How would you determine if a variation is direct or inverse from a given equation?
  2. How does the concept of proportionality apply to real-world situations like gas laws?
  3. If an inverse relationship is given, what happens to one variable when the other is doubled?
  4. What steps are involved in calculating the constant of proportionality for different types of variation?
  5. Can you provide examples of equations representing joint variation?

Tip: When working with variation problems, identify if the relationship is direct or inverse by checking if the variables multiply to a constant (inverse) or if one is a multiple of the other (direct).

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Math Problem Analysis

Mathematical Concepts

Direct Variation
Inverse Variation
Joint Variation
Combined Variation
Proportional Relationships

Formulas

Direct variation: y = kx
Inverse variation: y = k/x
Joint variation: y = kxz
Combined variation: y = (kx)/z

Theorems

Direct and inverse proportionality relationships

Suitable Grade Level

Grades 9-12