You're correct that the variance is equal to the square of the standard deviation, and the units should indeed be the square of the original units. Let's correct the calculation and ensure that it's rounded to four decimal places.

Given:

• Standard deviation ($s$) = 13.2965 kg

To find the variance ($s^2$), square the standard deviation:

$s^2 = (13.2965 \, \text{kg})^2 = 176.75026425 \, \text{kg}^2$

Now, rounding this to four decimal places:

$s^2 = 176.7503 \, \text{kg}^2$

So, the correct variance of the sample data is 176.7503 kg².

Would you like further details or have any questions?

Here are 5 related questions:

1. Why is it important to round to a specific number of decimal places in statistics?
2. How would you calculate the standard deviation if only the variance is provided?
3. What would the variance be if the standard deviation were doubled?
4. How does sample size affect the variance?
5. What is the difference between sample variance and population variance?

Tip: Always double-check your rounding to ensure accuracy, especially in statistical calculations!