Thank you for the clarification. Let's correct the solution based on a \( \frac{3}{4} \) turn instead of \( \frac{5}{4} \).

### Step-by-Step Explanation:

1. **Identifying the starting point:**
   - Alex starts facing the "Field."

2. **Understanding the turn:**
   - The turn is \( \frac{3}{4} \) of a complete turn.
   - A full turn in the circle means moving 360 degrees, which would bring you back to the starting point.
   - \( \frac{1}{4} \) of a turn corresponds to 90 degrees.
   - \( \frac{3}{4} \) of a turn means moving 270 degrees.

3. **Determining the direction and final position:**
   - The turn is anti-clockwise, so we move left from the starting point (Field).
   - From "Field":
     - A \( \frac{1}{4} \) turn brings you to "Parade Square."
     - A \( \frac{2}{4} \) (or \( \frac{1}{2} \)) turn brings you to "Dental Clinic."
     - A \( \frac{3}{4} \) turn brings you to "Foyer."

### Final Answer:
After making a \( \frac{3}{4} \) turn anti-clockwise, Alex will be facing **Foyer**.

Would you like more details on any part of this explanation? Here are some related questions:

1. How do we calculate the position after a \( \frac{1}{4} \) turn in any scenario?
2. How would the outcome change if the turn was clockwise instead?
3. What is the relationship between turns and angles in degrees?
4. How can we generalize this problem-solving method to different circular arrangements?
5. What happens if Alex starts from a different location, like "Canteen"?
6. Why is it important to understand the concept of direction in rotational movements?
7. How would this problem be solved if the turn was \( \frac{1}{2} \) instead?
8. What if the problem involved a continuous turn rather than a fraction?

**Tip:** When working with circular movements, visualize the problem as segments of a circle, and always move step-by-step to ensure accuracy.

Explore how to solve a problem involving a \( \frac{3}{4} \) turn in rotational movement. This detailed explanation covers the concepts of angles, rotations, and direction in a circular arrangement. Suitable for students in Grades 6-8.

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