Math Problem Statement

A 3 × 3 matrix B is known to have eigenvalues 0, 1, 2. This information is enough to find three of these: a. the rank of B, b. the determinant of BT B, c. the eigenvalues of BT B, d. the eigenvalues of (B + I)^(-1) Mark your choices. Explain/justify

Solution

Given that a 3×33 \times 3 matrix BB has eigenvalues 00, 11, and 22, we can analyze the options one by one:

a. The rank of BB:

The rank of a matrix is the dimension of its column space (or row space), which is the same as the number of non-zero eigenvalues.

  • Since BB has eigenvalues 00, 11, and 22, the non-zero eigenvalues are 11 and 22.
  • Thus, the rank of BB is 22 (since the eigenvalue 00 contributes nothing to the rank).

Conclusion: The rank of BB can be determined. (Correct choice)

b. The determinant of BTBB^T B:

The determinant of a matrix is the product of its eigenvalues.

  • BTBB^T B is a symmetric matrix, and its eigenvalues are the squares of the singular values of BB, which are the absolute values of the eigenvalues of BB.
  • The eigenvalues of BB are 00, 11, and 22, so the eigenvalues of BTBB^T B are 02=00^2 = 0, 12=11^2 = 1, and 22=42^2 = 4.
  • The determinant of BTBB^T B is the product of these eigenvalues: 0×1×4=00 \times 1 \times 4 = 0.

Conclusion: The determinant of BTBB^T B can be determined. (Correct choice)

c. The eigenvalues of BTBB^T B:

  • As discussed in part (b), the eigenvalues of BTBB^T B are the squares of the absolute values of the eigenvalues of BB.
  • Given that the eigenvalues of BB are 00, 11, and 22, the eigenvalues of BTBB^T B are 00, 11, and 44.

Conclusion: The eigenvalues of BTBB^T B can be determined. (Correct choice)

d. The eigenvalues of (B+I)1(B + I)^{-1}:

To determine the eigenvalues of (B+I)1(B + I)^{-1}, we can use the fact that if λ\lambda is an eigenvalue of BB, then 1λ+1\frac{1}{\lambda + 1} will be an eigenvalue of (B+I)1(B + I)^{-1}.

  • The eigenvalues of BB are 00, 11, and 22.
  • Thus, the eigenvalues of B+IB + I will be 0+1=10 + 1 = 1, 1+1=21 + 1 = 2, and 2+1=32 + 1 = 3.
  • The eigenvalues of (B+I)1(B + I)^{-1} will be 11=1\frac{1}{1} = 1, 12=0.5\frac{1}{2} = 0.5, and 130.333\frac{1}{3} \approx 0.333.

Conclusion: The eigenvalues of (B+I)1(B + I)^{-1} can be determined. (Correct choice)

Final Conclusion:

All four choices aa, bb, cc, and dd can be determined from the given information about the eigenvalues of BB.

Would you like further details on any of these points? Here are five related questions:

  1. How is the rank of a matrix related to its eigenvalues?
  2. What does the determinant of a matrix tell us about its eigenvalues?
  3. How are the eigenvalues of BB related to the eigenvalues of BTBB^T B?
  4. Can the eigenvalues of a matrix be negative, and how does that affect the eigenvalues of BTBB^T B?
  5. What properties of a matrix are preserved under similarity transformations?

Tip: Understanding how eigenvalues transform under matrix operations can help solve a wide range of problems in linear algebra.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Eigenvalues
Matrix Operations

Formulas

Rank definition
Determinant of a matrix
Eigenvalue relation for matrix products

Theorems

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Suitable Grade Level

Undergraduate