Math Problem Statement

ыщдму ершы зкщидуь гыштп mathematical induction

Solution

It seems like you're asking about mathematical induction. Let me explain what it is.

Mathematical induction is a method of mathematical proof typically used to prove that a statement holds for all natural numbers (or some infinite sequence). The basic idea is to prove the base case first, and then prove that if the statement holds for one number, it holds for the next one as well.

Steps of Mathematical Induction:

  1. Base Case: Prove that the statement is true for the initial value, often n=1n = 1 or n=0n = 0.

  2. Inductive Step:

    • Assume the statement is true for n=kn = k (this is called the inductive hypothesis).
    • Then, prove that if the statement holds for n=kn = k, it must also hold for n=k+1n = k+1.

If both the base case and the inductive step are true, the statement is true for all nn starting from the base case.

Example: Proving the sum of the first nn natural numbers.

Let's prove that 1+2+3++n=n(n+1)21 + 2 + 3 + \dots + n = \frac{n(n+1)}{2} using induction.

  1. Base Case: For n=1n = 1: 1=1(1+1)2=11 = \frac{1(1+1)}{2} = 1 The statement is true for n=1n = 1.

  2. Inductive Hypothesis: Assume the statement is true for n=kn = k, i.e., 1+2+3++k=k(k+1)2.1 + 2 + 3 + \dots + k = \frac{k(k+1)}{2}.

  3. Inductive Step: We need to show that the statement holds for n=k+1n = k+1: 1+2+3++k+(k+1)=(k+1)((k+1)+1)2.1 + 2 + 3 + \dots + k + (k+1) = \frac{(k+1)((k+1)+1)}{2}. Start with the inductive hypothesis: [ 1 +

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Math Problem Analysis

Mathematical Concepts

Mathematical Induction
Natural Numbers
Proof

Formulas

Sum of first n natural numbers: (n(n+1))/2

Theorems

Principle of Mathematical Induction

Suitable Grade Level

Grades 10-12