Math Problem Statement

Consider the graph of y = f(x) shown. Find f(-1), lim(x→−1−)f(x), lim(x→−1+)f(x), and lim(x→−1)f(x) based on the graph.

Solution

Let's analyze the graph and answer the questions provided.

  1. f(1)f(-1)

To find f(1)f(-1), we look at the y-coordinate of the point where x=1x = -1. From the graph, at x=1x = -1, y=3y = 3. Therefore, f(1)=3f(-1) = 3.

  1. limx1f(x)\lim_{x \to -1^-} f(x)

The limit of f(x)f(x) as xx approaches 1-1 from the left. From the graph, as xx approaches 1-1 from the left, f(x)f(x) approaches 33. Therefore, limx1f(x)=3\lim_{x \to -1^-} f(x) = 3.

  1. limx1+f(x)\lim_{x \to -1^+} f(x)

The limit of f(x)f(x) as xx approaches 1-1 from the right. From the graph, as xx approaches 1-1 from the right, f(x)f(x) also approaches 33. Therefore, limx1+f(x)=3\lim_{x \to -1^+} f(x) = 3.

  1. limx1f(x)\lim_{x \to -1} f(x)

Since both the left-hand limit and the right-hand limit as xx approaches 1-1 are equal and both are 33, the limit of f(x)f(x) as xx approaches 1-1 exists and is 33. Therefore, limx1f(x)=3\lim_{x \to -1} f(x) = 3.

To summarize, the answers are:

  1. f(1)=3f(-1) = 3
  2. limx1f(x)=3\lim_{x \to -1^-} f(x) = 3
  3. limx1+f(x)=3\lim_{x \to -1^+} f(x) = 3
  4. limx1f(x)=3\lim_{x \to -1} f(x) = 3

Would you like any further details or have any questions about these solutions? Here are some related questions you might find useful:

  1. What are the definitions of left-hand limit and right-hand limit?
  2. How do we determine if a limit exists at a point?
  3. What is the difference between a limit and a function value at a point?
  4. Can a function be discontinuous at a point where its limit exists?
  5. How do you identify and interpret discontinuities in a graph?

Tip: Always compare the left-hand and right-hand limits at a point to determine if the overall limit exists.

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Math Problem Analysis

Mathematical Concepts

Limits
Continuity
Piecewise Functions

Formulas

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Theorems

Left-hand and right-hand limits
Limit definition

Suitable Grade Level

Grades 10-12