Math Problem Statement

The domain of f(x) is [2, 20) and the range is (-4, 12). What is the domain and range of f^-1(x)

Solution

The domain and range of the inverse function f1(x)f^{-1}(x) are determined by swapping the domain and range of the original function f(x)f(x).

Given:

  • The domain of f(x)f(x) is [2,20)[2, 20)
  • The range of f(x)f(x) is (4,12)(-4, 12)

For the inverse function f1(x)f^{-1}(x):

  • The domain of f1(x)f^{-1}(x) is the range of f(x)f(x)
  • The range of f1(x)f^{-1}(x) is the domain of f(x)f(x)

Therefore:

  • The domain of f1(x)f^{-1}(x) is (4,12)(-4, 12)
  • The range of f1(x)f^{-1}(x) is [2,20)[2, 20)

If you have any questions or need further details, please let me know. Here are some additional questions you might consider:

  1. How do you find the inverse of a function?
  2. What are the conditions for a function to have an inverse?
  3. How do you graph the inverse of a function?
  4. What is the relationship between the derivative of a function and its inverse?
  5. How do you determine if a function is one-to-one?

Tip: When finding the inverse of a function, it's helpful to interchange the roles of xx and yy and solve for the new yy. This process helps in understanding the relationship between a function and its inverse.