Math Problem Statement

1tan(5xπ) \frac{1}{\tan}\cdot\left(5\cdot x-\pi\right)\text{ }

Solution

The expression you provided is:

1tan(5xπ)\frac{1}{\tan}\cdot\left(5\cdot x-\pi\right)

To interpret this expression correctly, it's important to determine how the components are intended to be grouped. Based on standard mathematical notation, let's clarify what the expression likely means.

Interpreting the Expression

If we consider the expression:

1tan(5xπ)\frac{1}{\tan}\cdot\left(5\cdot x-\pi\right)

It can be interpreted as:

1tan(5xπ)\frac{1}{\tan(5x - \pi)}

This is because the notation 1tan\frac{1}{\tan} suggests taking the reciprocal of the tangent function applied to the entire expression 5xπ5x - \pi.

Simplifying the Expression

To simplify 1tan(5xπ)\frac{1}{\tan(5x - \pi)}, we use the trigonometric identity that relates the tangent function and the cotangent function:

1tan(θ)=cot(θ)\frac{1}{\tan(\theta)} = \cot(\theta)

Thus, the expression can be rewritten as:

cot(5xπ)\cot(5x - \pi)

Conclusion

The expression 1tan(5xπ)\frac{1}{\tan}(5x - \pi) simplifies to cot(5xπ)\cot(5x - \pi). The cotangent function, cot(θ)\cot(\theta), is the reciprocal of the tangent function, meaning it gives the ratio of the adjacent side to the opposite side in a right triangle or, equivalently, cot(θ)=cos(θ)sin(θ)\cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)}.

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Follow-Up Questions

  1. Would you like to know how to graph the cotangent function?
  2. Do you want to see an example of evaluating cot(5xπ)\cot(5x - \pi) for a specific value of xx?
  3. Are you interested in understanding the periodicity of the cotangent function?
  4. Would you like an explanation of how to convert between cotangent and other trigonometric functions?
  5. Do you want to explore the derivatives or integrals involving the cotangent function?

Tip

Remember that understanding the reciprocal relationships between trigonometric functions, such as tan(θ)\tan(\theta) and cot(θ)\cot(\theta), can help simplify complex trigonometric expressions!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Reciprocal Functions

Formulas

\( \frac{1}{\tan(\theta)} = \cot(\theta) \)

Theorems

Relationships between trigonometric functions

Suitable Grade Level

High School