Math Problem Statement

how does E ̅(z,t)=|〖E_0〗_x a ̂_x | cos⁡(ωt+ϕ_0 ) B ̅(z,t)=|〖B_0〗_y a ̂_y | cos⁡(ωt+ϕ_0 ) equate to B(z,t)=B_0 a ̂_y cos(kz−ωt)

Solution

The equations you're working with describe the electric field E(z,t)\vec{E}(z,t) and magnetic field B(z,t)\vec{B}(z,t) in a plane electromagnetic wave.

Let's analyze the equations one step at a time and figure out how the given E(z,t)\vec{E}(z,t) and B(z,t)\vec{B}(z,t) expressions lead to the simplified form for B(z,t)\vec{B}(z,t).

1. Initial Forms:

You have the initial electric and magnetic fields:

E(z,t)=E0xa^xcos(ωt+φ0)\vec{E}(z,t) = |E_{0x} \hat{a}_x| \cos(\omega t + \varphi_0) B(z,t)=B0ya^ycos(ωt+φ0)\vec{B}(z,t) = |B_{0y} \hat{a}_y| \cos(\omega t + \varphi_0)

These represent oscillations of the electric and magnetic fields, where:

  • E0xE_{0x} and B0yB_{0y} are the amplitudes of the electric and magnetic fields, respectively.
  • ω\omega is the angular frequency of the wave.
  • φ0\varphi_0 is an initial phase.
  • The fields are polarized along a^x\hat{a}_x and a^y\hat{a}_y, respectively.

2. Simplified Magnetic Field Expression:

You want to show how the second equation for B(z,t)\vec{B}(z,t):

B(z,t)=B0a^ycos(kzωt)\vec{B}(z,t) = B_0 \hat{a}_y \cos(kz - \omega t)

arises. This is a standard expression for a traveling plane wave propagating in the zz-direction, where:

  • kk is the wave number, and it is related to the wavelength λ\lambda by k=2πλk = \frac{2\pi}{\lambda}.
  • ωt\omega t represents the time-dependent oscillation.
  • kzωtkz - \omega t shows that the wave is traveling in the positive zz-direction.

3. Reconciling the Two Forms:

  • In the initial expression for B(z,t)\vec{B}(z,t), there is no explicit dependence on zz, only tt. This suggests that the initial form represents the field at a specific point in space, or it's a simplified snapshot.

  • To convert to a traveling wave form, we need to introduce the spatial dependence on zz. This is done by assuming that the wave propagates in the zz-direction, leading to the phase factor kzωtkz - \omega t.

  • The phase shift φ0\varphi_0 in the original equation can be absorbed into the wave phase kzωtkz - \omega t by choosing the appropriate value of zz or adjusting the initial time t0t_0. Thus, the overall phase can be modified to fit the traveling wave form kzωtkz - \omega t.

4. Conclusion:

The transformation from:

B(z,t)=B0a^ycos(ωt+φ0)\vec{B}(z,t) = |B_0 \hat{a}_y| \cos(\omega t + \varphi_0)

to:

B(z,t)=B0a^ycos(kzωt)\vec{B}(z,t) = B_0 \hat{a}_y \cos(kz - \omega t)

is essentially the inclusion of the spatial dependence kzkz, which corresponds to the wave traveling along the zz-axis. The initial phase φ0\varphi_0 can be set to zero or incorporated into the wave's spatial dependence. The result is a typical expression for a plane electromagnetic wave.

Would you like more details, or do you have any specific questions on this?

Related Questions:

  1. How does the wave number kk relate to the frequency ω\omega in an electromagnetic wave?
  2. What is the relationship between the electric and magnetic fields in a traveling electromagnetic wave?
  3. How do we determine the direction of wave propagation from the phase factor kzωtkz - \omega t?
  4. Why can we absorb the phase φ0\varphi_0 into the term kzωtkz - \omega t?
  5. How does polarization affect the electric and magnetic field vectors in an EM wave?

Tip:

In electromagnetic waves, the electric and magnetic fields are always perpendicular to each other and to the direction of wave propagation. This is a key feature of transverse waves.

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Math Problem Analysis

Mathematical Concepts

Electromagnetic Waves
Wave Propagation
Trigonometric Functions
Wave Equations

Formulas

E̅(z,t) = E_0 â_x cos(ωt + ϕ_0)
B̅(z,t) = B_0 â_y cos(ωt + ϕ_0)
B(z,t) = B_0 â_y cos(kz - ωt)

Theorems

Plane Electromagnetic Wave Equation
Wave Number Relation: k = 2π / λ

Suitable Grade Level

University Level (Physics/Electromagnetism)