Math Problem Statement

  1. Mention the convolution integral with all combinations of integral limits( if the system is casual)?

Solution

The convolution integral is a fundamental concept in signal processing and systems theory, particularly when analyzing linear time-invariant (LTI) systems. For a system to be causal, the output at any time tt depends only on the current and past inputs, not on future inputs. This causality condition affects the limits of the convolution integral.

Given two functions x(t)x(t) (input signal) and h(t)h(t) (impulse response of the system), the convolution y(t)y(t) of these two functions is defined as:

y(t)=(xh)(t)=x(τ)h(tτ)dτy(t) = (x * h)(t) = \int_{-\infty}^{\infty} x(\tau) h(t - \tau) \, d\tau

However, for a causal system, the impulse response h(t)h(t) is zero for t<0t < 0. This causality simplifies the convolution integral. Depending on the time tt, the limits of the convolution integral vary:

1. For t<0t < 0:

y(t)=tx(τ)h(tτ)dτy(t) = \int_{-\infty}^{t} x(\tau) h(t - \tau) \, d\tau Since h(tτ)=0h(t - \tau) = 0 for τ>t\tau > t, the convolution integral only includes values where tτ0t - \tau \geq 0, i.e., τt\tau \leq t.

2. For t=0t = 0:

y(0)=0x(τ)h(τ)dτy(0) = \int_{-\infty}^{0} x(\tau) h(-\tau) \, d\tau At t=0t = 0, the integral is over all past times since h(τ)h(-\tau) is defined for τ0\tau \leq 0.

3. For t>0t > 0:

y(t)=0tx(τ)h(tτ)dτy(t) = \int_{0}^{t} x(\tau) h(t - \tau) \, d\tau Here, the limits of integration are from 0 to tt, because for a causal system h(tτ)h(t - \tau) is non-zero only when τ\tau is within the interval [0,t][0, t].

Summary of Integral Limits for a Causal System:

  • For t<0t < 0: The limits are from -\infty to tt.
  • For t=0t = 0: The limits are from -\infty to 0.
  • For t>0t > 0: The limits are from 0 to tt.

These conditions ensure that the output y(t)y(t) only depends on the present and past values of the input x(t)x(t), adhering to the causality of the system.

Would you like more details or have any specific questions?

Here are five related questions to deepen your understanding:

  1. How does the convolution integral change if the system is non-causal?
  2. What are the properties of the convolution operation in signal processing?
  3. Can you provide an example of computing the convolution integral for a given x(t)x(t) and h(t)h(t)?
  4. How does the convolution integral relate to the Laplace transform in analyzing LTI systems?
  5. What is the significance of the convolution theorem in Fourier analysis?

Tip: Always check the causality of a system before determining the limits of the convolution integral, as it affects the integral's evaluation and the system's behavior.

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Math Problem Analysis

Mathematical Concepts

Convolution
Causal Systems
Signal Processing

Formulas

Convolution integral: y(t) = (x * h)(t) = \int_{-\infty}^{\infty} x(\tau) h(t - \tau) \, d\tau

Theorems

-

Suitable Grade Level

Undergraduate