Math Problem Statement
the asymptotes are wrong
Solution
Let's re-evaluate the asymptotes for the given function .
Horizontal Asymptotes
To find the horizontal asymptotes, we analyze the behavior of the function as approaches and .
As : Divide the numerator and the denominator by : As , , so the limit is: Thus, there is a horizontal asymptote at .
As : As , . Therefore: Thus, there is a horizontal asymptote at .
Vertical Asymptotes
To find vertical asymptotes, we look for values of where the denominator is zero and the numerator is non-zero.
Setting the denominator equal to zero: Taking the natural logarithm of both sides:
At , the function's denominator is zero, which suggests a vertical asymptote at this point. We need to ensure the numerator does not also go to zero here:
Therefore, there is a vertical asymptote at:
Summary of Corrected Asymptotes
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Horizontal Asymptotes:
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Vertical Asymptote:
Would you like more details or have any questions about these steps?
Here are 5 questions you might ask next:
- How do you determine if a limit results in an indeterminate form?
- Can you explain the concept of horizontal and vertical asymptotes further?
- How do you find limits as approaches infinity or negative infinity?
- What are some techniques for solving exponential equations?
- Can you graph the function ?
Tip: When dealing with exponential functions, always check the behavior at infinity and negative infinity to accurately determine the horizontal asymptotes.
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Math Problem Analysis
Mathematical Concepts
Limits
Exponential Functions
Asymptotes
Formulas
Limit definition
Exponential function behavior
Theorems
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Suitable Grade Level
Advanced High School