To find the prime factorization of 120, let's break it down step-by-step:

1. Start with 120. Find its smallest prime factor:

   • 120 is even, so divide by 2:
     $120 \div 2 = 60$

2. Now, find the smallest prime factor of 60:

   • 60 is also even, so divide by 2:
     $60 \div 2 = 30$

3. Next, find the smallest prime factor of 30:

   • 30 is still even, so divide by 2:
     $30 \div 2 = 15$

4. Now, find the smallest prime factor of 15:

   • 15 is not even, but it is divisible by 3:
     $15 \div 3 = 5$

5. Finally, 5 is a prime number.

So, the complete prime factorization of 120 is: $120 = 2 \times 2 \times 2 \times 3 \times 5$

Now, listing the factors in order from least to greatest: $120 = 2 \times 2 \times 2 \times 3 \times 5$

Each number that appears in the prime factorization of 120 is: $2, 2, 2, 3, 5$

Would you like more details or have any questions?

Here are five related questions to explore further:

1. What is the prime factorization of 180?
2. How can you quickly identify if a number is prime?
3. What is the highest power of 2 that divides 120?
4. Can a prime factorization include numbers other than primes?
5. How does prime factorization help in finding the greatest common divisor (GCD)?

Tip: When performing prime factorization, always start with the smallest primes and work upward.