Math Problem Statement

A woman standing on a hill sees a flagpole that she knows is 35 ft tall. The angle of depression to the bottom of the pole is 14°, and the angle of elevation to the top of the pole is 18°. Find her distance x from the pole. (Round your answer to one decimal place.)

Solution

To solve this problem, we'll use trigonometric principles, specifically the tangent function. The problem gives us two angles: the angle of depression to the bottom of the flagpole (14°) and the angle of elevation to the top of the flagpole (18°). We'll break the problem into two parts to find the distance xx from the woman to the flagpole.

Step 1: Understanding the setup

  1. Height of the flagpole = 35 ft.
  2. Angle of depression to the bottom of the pole = 14°.
  3. Angle of elevation to the top of the pole = 18°.

Step 2: Define variables

Let:

  • xx be the horizontal distance from the woman to the pole.
  • hh be the height of the woman above the bottom of the pole.

Step 3: Use trigonometry

For the angle of elevation to the top of the pole:

  • We know that tan(18)=35+hx\tan(18^\circ) = \frac{35 + h}{x}.

For the angle of depression to the bottom of the pole:

  • We know that tan(14)=hx\tan(14^\circ) = \frac{h}{x}.

Step 4: Solve for xx

We can set up two equations from the tangent functions:

  1. tan(18)=35+hx\tan(18^\circ) = \frac{35 + h}{x}x=35+htan(18)x = \frac{35 + h}{\tan(18^\circ)}
  2. tan(14)=hx\tan(14^\circ) = \frac{h}{x}h=xtan(14)h = x \cdot \tan(14^\circ)

Now, substitute the expression for hh from the second equation into the first equation:

x=35+xtan(14)tan(18)x = \frac{35 + x \cdot \tan(14^\circ)}{\tan(18^\circ)}

Step 5: Solve for xx

Let's solve this equation numerically:

xtan(18)=35+xtan(14)x \cdot \tan(18^\circ) = 35 + x \cdot \tan(14^\circ)

x(tan(18)tan(14))=35x \cdot (\tan(18^\circ) - \tan(14^\circ)) = 35

x=35tan(18)tan(14)x = \frac{35}{\tan(18^\circ) - \tan(14^\circ)}

Step 6: Calculate the final answer

Now, calculate the value of xx using the tangents of the given angles.

x=35tan(18)tan(14)x = \frac{35}{\tan(18^\circ) - \tan(14^\circ)}

Let's compute this value:

x350.32490.2493350.0756462.0 ftx \approx \frac{35}{0.3249 - 0.2493} \approx \frac{35}{0.0756} \approx 462.0 \text{ ft}

So, the distance xx from the woman to the pole is approximately 462.0 feet.

Would you like further details or have any questions?

Here are five related questions to explore:

  1. How would the problem change if the height of the flagpole were different?
  2. What if the angles of elevation and depression were swapped?
  3. How would you solve the problem if only one of the angles was given?
  4. Can you derive a general formula for any similar situation?
  5. How does the problem change if the flagpole is on a flat surface instead of a hill?

Tip: Always double-check the trigonometric values, as small errors can lead to significantly different results in real-world applications.