Math Problem Statement

Find the solutions to the math problems provided in the uploaded image.

Solution

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Problem 1:

Find the value of cos5π3\cos \frac{5\pi}{3}.

Solution: cos5π3=cos(2ππ3)=cosπ3=12\cos \frac{5\pi}{3} = \cos \left( 2\pi - \frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}

Answer: B) 12\text{B) } \frac{1}{2}


Problem 2:

Find the value of sin13cos167+sin77sin167\sin 13^\circ \cos 167^\circ + \sin 77^\circ \sin 167^\circ.

Using the formula: sinAcosB+cosAsinB=sin(A+B)\sin A \cos B + \cos A \sin B = \sin(A + B) sin13cos167+sin77sin167=sin(13+167)=sin180=0\sin 13^\circ \cos 167^\circ + \sin 77^\circ \sin 167^\circ = \sin(13^\circ + 167^\circ) = \sin 180^\circ = 0

Answer: B) 0\text{B) 0}


Problem 3:

Simplify cot(α120)\cot(\alpha - 120^\circ).

Using trigonometric identities: cot(α120)=cotα+313cotα\cot(\alpha - 120^\circ) = \frac{\cot \alpha + \sqrt{3}}{1 - \sqrt{3}\cot \alpha}

Answer: D) 3cotα+1cotα+3\text{D) } \frac{\sqrt{3} \cot \alpha + 1}{\cot \alpha + \sqrt{3}}


Problem 4:

Find the value of

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Logarithms
Algebra
Inequalities

Formulas

cos(x) = cos(2π - x)
sin(A)cos(B) + cos(A)sin(B) = sin(A + B)
cot(α - β) = (cotα + cotβ) / (1 - cotαcotβ)
log_a(b) is defined if a > 0, a ≠ 1, and b > 0

Theorems

Trigonometric identities
Properties of logarithms
Double-angle identities

Suitable Grade Level

Grades 9-12