Math Problem Statement

Solve the following equations: a) 20^(3x-7) = 2 * 8^(2x-5) b) 4^x = (6.05 * x) / 3 c) x^(7 + 3*log(x)) = 10 * x^5 d) 5^(3x) = 5^(2x + 12) f) ln(2x + 5) = ln(3x - 7) g) 6^x = 7x + 10 h) ln(x) = 7 j) e^(2 * ln(x)) = e k) 3^x = 5^(x + 2) l) 4 * 6^(x-1) = 3 * 2^(x+1) m) x * log(x) = 1 o) x^(1 + log(x)) = 100

Solution

I see you've uploaded a math exercise sheet containing equations to solve. It seems like you need help solving some of them. Let's go through a few of the problems:


a) 203x7=282x520^{3x-7} = 2 \cdot 8^{2x-5}

This equation involves exponents and bases. We can first express 88 as 232^3 to simplify it.

So, the equation becomes: 203x7=2(23)2x520^{3x - 7} = 2 \cdot (2^3)^{2x - 5} Now, we simplify and solve for xx.


b) 4x=6.05x34^{x} = \frac{6.05 \cdot x}{3}

This equation has both an exponential term and a linear term. To solve it, we would need to take the logarithm of both sides.


c) x7+3log(x)=10x5x^{7 + 3 \log(x)} = 10 \cdot x^5

Here, we can apply logarithmic properties to simplify the equation. First, take the logarithm of both sides.


d) 53x=52x+125^{3x} = 5^{2x + 12}

This equation has the same base on both sides, so we can set the exponents equal to each other to solve for xx.


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Math Problem Analysis

Mathematical Concepts

Exponential Equations
Logarithmic Equations
Logarithmic Properties
Algebra

Formulas

a^b = c (Exponential equation)
log(a * b) = log(a) + log(b) (Logarithmic properties)
ln(a^b) = b * ln(a) (Logarithmic identity)
e^(ln(x)) = x (Exponential and logarithmic identity)

Theorems

Properties of logarithms
Exponentiation rules
Inverse properties of logarithms

Suitable Grade Level

Grades 9-11