Math Problem Statement
Solution
Let's go through each part of the problem:
(a) Find the ratio of the length of the side opposite to the length of the hypotenuse for each triangle. Round your answers to the nearest hundredth.
-
Triangle :
- Opposite side: units
- Hypotenuse: units
- Ratio:
-
Triangle :
- Opposite side: units
- Hypotenuse: units
- Ratio:
-
Triangle :
- Opposite side: units
- Hypotenuse: units
- Ratio:
Let's calculate these ratios.
(b) Use trigonometric functions to find , , and . Round your answers to the nearest hundredth.
Let's compute these values:
(c) Identify which trigonometric function gives each ratio of sides in part (a).
We will identify whether it's sine, cosine, or tangent.
Now, let's do the calculations:### Calculations:
(a) Ratios of the side opposite to the hypotenuse:
- For : (rounded to the nearest hundredth)
- For : (rounded to the nearest hundredth)
- For : (rounded to the nearest hundredth)
(b) Trigonometric function values for :
(c) Identification of the trigonometric function that matches the ratios: The ratios , , and are closest to the value of , which suggests that these ratios represent the sine function.
Answer for (c): The correct trigonometric function is sine.
Would you like further details or have any questions?
Related Questions:
- How do you find the ratios using cosine and tangent functions?
- How would the ratios change if the angles were different?
- What is the relationship between the sine and cosine of complementary angles?
- How do these values help in solving real-world problems involving right triangles?
- What are some applications of trigonometric ratios in engineering?
Tip: Always check the units when calculating trigonometric values, especially when rounding.
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Right Triangles
Ratios
Formulas
sin(θ) = opposite/hypotenuse
cos(θ) = adjacent/hypotenuse
tan(θ) = opposite/adjacent
Theorems
Trigonometric Ratios
Suitable Grade Level
Grades 9-10
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