Math Problem Statement

Thank you. Is there an equivalent identity for the expression sin(a+b)? Where a and b are angles. Perhaps with trigonometry

Solution

Yes, there is an equivalent trigonometric identity for sin(a+b)\sin(a + b). This identity is known as the sum of angles formula for sine. It expresses the sine of a sum of two angles in terms of the sines and cosines of the individual angles.

The identity is:

sin(a+b)=sin(a)cos(b)+cos(a)sin(b)\sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b)

Explanation

This identity can be very useful in various trigonometric problems and simplifies the process of finding the sine of a sum of two angles.

Derivation (Outline)

To understand why this identity works, consider the following geometric or unit circle approach:

  1. Unit Circle Approach:

    • Draw angles aa and bb on the unit circle.
    • Use the coordinates of the points on the unit circle corresponding to these angles and apply the angle addition formula for coordinates to derive the sine and cosine of the resulting angle.
  2. Algebraic Approach:

    • Use the Euler's formula for complex exponentials: eix=cos(x)+isin(x)e^{ix} = \cos(x) + i\sin(x).
    • Express the sum of two angles using complex exponentials and separate the real and imaginary parts to derive the sine and cosine identities.

Example

Let's apply this identity to an example. Suppose a=30a = 30^\circ and b=45b = 45^\circ:

sin(30+45)=sin(75)\sin(30^\circ + 45^\circ) = \sin(75^\circ)

Using the identity:

sin(75)=sin(30)cos(45)+cos(30)sin(45)\sin(75^\circ) = \sin(30^\circ) \cos(45^\circ) + \cos(30^\circ) \sin(45^\circ)

We know the exact values of these trigonometric functions:

  • sin(30)=12\sin(30^\circ) = \frac{1}{2}
  • cos(30)=32\cos(30^\circ) = \frac{\sqrt{3}}{2}
  • sin(45)=cos(45)=22\sin(45^\circ) = \cos(45^\circ) = \frac{\sqrt{2}}{2}

Substitute these values into the identity:

sin(75)=(12)(22)+(32)(22)\sin(75^\circ) = \left(\frac{1}{2}\right) \left(\frac{\sqrt{2}}{2}\right) + \left(\frac{\sqrt{3}}{2}\right) \left(\frac{\sqrt{2}}{2}\right)

sin(75)=24+64\sin(75^\circ) = \frac{\sqrt{2}}{4} + \frac{\sqrt{6}}{4}

sin(75)=2+64\sin(75^\circ) = \frac{\sqrt{2} + \sqrt{6}}{4}

This gives us the exact value of sin(75)\sin(75^\circ) using the sum of angles formula.

Would you like more details or have any questions?

Relative Questions

  1. What are the cosine and tangent identities for the sum of two angles?
  2. How can we derive the sine and cosine identities using the unit circle?
  3. What is the sine of the difference of two angles (sin(ab)\sin(a - b))?
  4. How can we use the sum of angles formula to solve trigonometric equations?
  5. Can the sum of angles identity be used in solving real-world problems?
  6. What are some applications of the sum of angles identity in physics?
  7. How do you simplify expressions involving sin(a+b)\sin(a + b) and cos(a+b)\cos(a + b)?
  8. What are the sine and cosine double-angle identities?

Tip

When working with trigonometric identities, practice deriving and using them in various contexts to become more familiar with their applications and the relationships between different trigonometric functions.

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Math Problem Analysis

Mathematical Concepts

Trigonometry

Formulas

Sum of angles formula for sine: \( \sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b) \)

Theorems

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Suitable Grade Level

Advanced High School