Math Problem Statement

What trigonometric function has a period of π, a range of [-2, 0], and contains the point (π/4, -2)?

Solution

The image provides the following information:

  • Period: π\pi
  • Range: [2,0][-2, 0]
  • Contains the point: (π4,2)\left( \frac{\pi}{4}, -2 \right)

Based on these details, the function described could potentially be a trigonometric function like a cosine or sine function that has been transformed vertically. Here's what we can deduce:

  1. The period of the function is π\pi, indicating that the function repeats every π\pi units along the x-axis.
  2. The range is [2,0][-2, 0], meaning the output (y-values) stays between -2 and 0. This suggests the function has been vertically shifted or scaled down.
  3. The function contains the point (π4,2)\left( \frac{\pi}{4}, -2 \right), which gives us specific information about the value of the function at x=π4x = \frac{\pi}{4}.

Given these facts, the function could be of the form: y=2cos(2x)y = -2 \cos(2x) or y=2sin(2x)y = -2 \sin(2x) These forms would satisfy the period, range, and given point conditions.

Would you like more details on how this equation was derived, or have any questions on this topic?

Related Questions:

  1. How does a function's period affect its graph?
  2. What does the range of a trigonometric function indicate?
  3. How are trigonometric functions transformed vertically and horizontally?
  4. What is the significance of specific points on the graph of a trigonometric function?
  5. How does the frequency of a trigonometric function relate to its period?

Tip:

When analyzing trigonometric functions, the period and range provide essential clues about the function's shape and transformations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometric Functions
Periodicity
Range

Formulas

y = -2 cos(2x)
y = -2 sin(2x)

Theorems

Trigonometric Periodicity
Range of Trigonometric Functions

Suitable Grade Level

Grades 10-12