Math Problem Statement

Diketahui tan α° = - dan α° sudut di kuadran II. Hitunglah: (sin(90° − α°) − cos(180° − α°)) / (tan(270° + α°) + cot(360° − α°))

Solution

The question in the image is a trigonometric expression. The problem states:

  • Given that tanα=\tan \alpha^\circ = - (implying tanα\tan \alpha^\circ is negative) and α\alpha^\circ is in the second quadrant.
  • We need to calculate the following expression:

sin(90α)cos(180α)tan(270+α)+cot(360α)\frac{\sin(90^\circ - \alpha^\circ) - \cos(180^\circ - \alpha^\circ)}{\tan(270^\circ + \alpha^\circ) + \cot(360^\circ - \alpha^\circ)}

Step-by-step solution:

  1. Identify trigonometric identities in terms of α\alpha^\circ:

    • sin(90α)=cos(α)\sin(90^\circ - \alpha^\circ) = \cos(\alpha^\circ) (co-function identity)
    • cos(180α)=cos(α)\cos(180^\circ - \alpha^\circ) = -\cos(\alpha^\circ) (because cos\cos is negative in the second quadrant)
    • tan(270+α)=cot(α)\tan(270^\circ + \alpha^\circ) = \cot(\alpha^\circ) (since tan(270+x)=cot(x)\tan(270^\circ + x) = \cot(x))
    • cot(360α)=cot(α)\cot(360^\circ - \alpha^\circ) = \cot(\alpha^\circ) (as cot\cot repeats every 180 degrees)
  2. Substitute the identities: The expression simplifies to:

    cos(α)(cos(α))cot(α)+cot(α)\frac{\cos(\alpha^\circ) - (-\cos(\alpha^\circ))}{\cot(\alpha^\circ) + \cot(\alpha^\circ)}

    This simplifies to:

    cos(α)+cos(α)2cot(α)\frac{\cos(\alpha^\circ) + \cos(\alpha^\circ)}{2 \cdot \cot(\alpha^\circ)}

    Which further simplifies to:

    2cos(α)2cot(α)=cos(α)cot(α)\frac{2\cos(\alpha^\circ)}{2 \cdot \cot(\alpha^\circ)} = \frac{\cos(\alpha^\circ)}{\cot(\alpha^\circ)}

  3. Simplify the final result: Since cos(α)cot(α)=sin(α)\frac{\cos(\alpha^\circ)}{\cot(\alpha^\circ)} = \sin(\alpha^\circ), the final answer is:

    sin(α)\sin(\alpha^\circ)

Would you like further clarification on this solution or details on any specific steps?


Here are 5 follow-up questions that could help expand your understanding:

  1. Why is tanα\tan \alpha^\circ negative in the second quadrant?
  2. Can you explain how the co-function identities are derived?
  3. How does the periodicity of trigonometric functions help simplify expressions?
  4. What is the relationship between tan\tan and cot\cot?
  5. How would this problem change if α\alpha^\circ were in a different quadrant?

Tip: Always verify the quadrant of an angle when solving trigonometric problems to ensure correct sign usage for sine, cosine, and tangent.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities
Quadrants

Formulas

sin(90° − α°) = cos(α°)
cos(180° − α°) = -cos(α°)
tan(270° + α°) = cot(α°)
cot(360° − α°) = cot(α°)

Theorems

Co-function Identities
Trigonometric Functions in Different Quadrants

Suitable Grade Level

Grades 10-12