Math Problem Statement

From some distance away, you measure the angle of elevation to the top of a tree to be 30 degrees. Walking 20 feet closer, you measure the angle of elevation to be 45 degrees. How tall is the tree? No decimal answers, solution is exact.

Solution

We are given that the angle of elevation to the top of a tree changes as we move closer. First, we measure the angle of elevation as 3030^\circ, and then after walking 20 feet closer, the angle becomes 4545^\circ. We are tasked with finding the exact height of the tree.

Step-by-Step Solution

  1. Define Variables:

    • Let hh be the height of the tree.
    • Let dd be the initial distance from the tree when the angle of elevation is 3030^\circ.
  2. Apply Trigonometry: From the point where the angle of elevation is 3030^\circ, we can set up a relationship using the tangent of the angle: tan(30)=hd\tan(30^\circ) = \frac{h}{d} Since tan(30)=13\tan(30^\circ) = \frac{1}{\sqrt{3}}, this gives: 13=hd\frac{1}{\sqrt{3}} = \frac{h}{d} Solving for hh, we get: h = \frac{d}{\sqrt{3}} \tag{1}

  3. Use the New Position: After walking 20 feet closer, the distance to the tree becomes d20d - 20 feet, and the angle of elevation is 4545^\circ. Using the tangent of 4545^\circ, we get: tan(45)=hd20\tan(45^\circ) = \frac{h}{d - 20} Since tan(45)=1\tan(45^\circ) = 1, this simplifies to: 1=hd201 = \frac{h}{d - 20} Solving for hh, we have: h = d - 20 \tag{2}

  4. Set Up a System of Equations: From equation (1), we know that h=d3h = \frac{d}{\sqrt{3}}, and from equation (2), h=d20h = d - 20. Equating the two expressions for hh, we get: d3=d20\frac{d}{\sqrt{3}} = d - 20

  5. Solve for dd: Multiply both sides of the equation by 3\sqrt{3} to eliminate the fraction: d=3(d20)d = \sqrt{3}(d - 20) Expanding the right-hand side: d=3d203d = \sqrt{3}d - 20\sqrt{3} Now, bring all terms involving dd to one side: d3d=203d - \sqrt{3}d = -20\sqrt{3} Factor out dd: d(13)=203d(1 - \sqrt{3}) = -20\sqrt{3} Solving for dd: d=20313d = \frac{-20\sqrt{3}}{1 - \sqrt{3}}

    To rationalize the denominator, multiply the numerator and denominator by 1+31 + \sqrt{3}: d=203(1+3)(13)(1+3)d = \frac{-20\sqrt{3}(1 + \sqrt{3})}{(1 - \sqrt{3})(1 + \sqrt{3})} Simplifying the denominator using the difference of squares: d=203(1+3)12(3)2=203(1+3)13=203(1+3)2d = \frac{-20\sqrt{3}(1 + \sqrt{3})}{1^2 - (\sqrt{3})^2} = \frac{-20\sqrt{3}(1 + \sqrt{3})}{1 - 3} = \frac{-20\sqrt{3}(1 + \sqrt{3})}{-2} Simplifying the expression: d=103(1+3)=103+30d = 10\sqrt{3}(1 + \sqrt{3}) = 10\sqrt{3} + 30

  6. Find the Height of the Tree: Using equation (2), we now find hh. Since h=d20h = d - 20, substitute d=103+30d = 10\sqrt{3} + 30: h=(103+30)20=103+10h = (10\sqrt{3} + 30) - 20 = 10\sqrt{3} + 10

Thus, the exact height of the tree is 103+10\boxed{10\sqrt{3} + 10} feet.

Would you like to go over any particular part of the solution, or do you have further questions?


Here are 5 related questions:

  1. What is the height of the tree if the second angle of elevation were different?
  2. How would the solution change if the tree were on a slope?
  3. Can you solve for the distance to the tree using another method?
  4. How would the problem change if both distances and angles were given?
  5. What is the significance of rationalizing the denominator in trigonometric problems?

Tip: Always check for alternative trigonometric identities that might simplify complex expressions in word problems.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Angle of Elevation
Tangent Function
System of Equations

Formulas

tan(θ) = opposite / adjacent
h = d / √3
h = d - 20
Difference of squares: (a - b)(a + b) = a^2 - b^2

Theorems

Trigonometric identity for tangent
Rationalization of the denominator

Suitable Grade Level

Grades 9-12