Math Problem Statement

Determine whether each of the given proportionality statements related to the triangle with a parallel segment are true or false.

Solution

To solve the problem, let's analyze the figure and equations given. The triangle is divided into segments by a line ED\overline{ED} that is parallel to BC\overline{BC}. This means we can apply the Basic Proportionality Theorem (Thales' Theorem), which states that:

If a line is drawn parallel to one side of a triangle and intersects the other two sides, then it divides the two sides in the same ratio.

Thus, for triangle ABC\triangle ABC, with EDBC\overline{ED} \parallel \overline{BC}, the following proportionality relationships hold true: ADDB=AEEC.\frac{AD}{DB} = \frac{AE}{EC}.

Let us evaluate each statement:


1. ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC}

This is directly based on the Basic Proportionality Theorem, so True.


2. DBAB=AEAC\frac{DB}{AB} = \frac{AE}{AC}

Here, AB=AD+DBAB = AD + DB and AC=AE+ECAC = AE + EC. Dividing each term as DBAB\frac{DB}{AB} and AEAC\frac{AE}{AC}, the relationship follows proportionality. Hence, True.


3. ADAE=DBEC\frac{AD}{AE} = \frac{DB}{EC}

Using the proportionality rule, the ratios ADDB\frac{AD}{DB} and AEEC\frac{AE}{EC} are equal. Rewriting: ADAE=DBEC.\frac{AD}{AE} = \frac{DB}{EC}. Thus, this statement is True.


4. DBAE=ADEC\frac{DB}{AE} = \frac{AD}{EC}

Rewriting the relationship ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC} does not imply that DBAE=ADEC\frac{DB}{AE} = \frac{AD}{EC}. This is a mismatch. Hence, False.


5. ADAB=AEAC\frac{AD}{AB} = \frac{AE}{AC}

Using proportionality and the segment definitions (AB=AD+DBAB = AD + DB, AC=AE+ECAC = AE + EC), we find this statement holds. Hence, True.


6. ADAB=ECAC\frac{AD}{AB} = \frac{EC}{AC}

This is incorrect because ADAB\frac{AD}{AB} should correspond to AEAC\frac{AE}{AC}, not ECAC\frac{EC}{AC}. Hence, False.


Final Answers:

  1. True
  2. True
  3. True
  4. False
  5. True
  6. False

Would you like further clarification or detailed steps?

Here are 5 questions related to this topic:

  1. What is the Basic Proportionality Theorem, and how is it applied?
  2. How can the proportionality be proven using similar triangles?
  3. Why does parallelism between ED\overline{ED} and BC\overline{BC} matter?
  4. How do we derive segment proportions from larger triangles?
  5. Can proportionality hold if the dividing line is not parallel?

Tip: Always verify whether given lines are parallel before applying the Basic Proportionality Theorem.

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Math Problem Analysis

Mathematical Concepts

Geometry
Triangle Proportionality
Ratios

Formulas

\( \frac{AD}{DB} = \frac{AE}{EC} \) (Basic Proportionality Theorem)
\( AB = AD + DB \)
\( AC = AE + EC \)

Theorems

Basic Proportionality Theorem (Thales' Theorem)

Suitable Grade Level

Grades 8-10