Math Problem Statement

The points Nleft parenthesis, 5, comma, 5, right parenthesis(5,5), Oleft parenthesis, 3, comma, minus, 4, right parenthesis(3,−4), and Pleft parenthesis, minus, 2, comma, minus, 1, right parenthesis(−2,−1) form a triangle. Plot the points then click the "Graph Triangle" button., On this question page, you will first graph points on a coordinate grid. Following the graph are two buttons, "Graph Triangle" will drawn lines between your points, and "Reset" will remove all of your points. Once you press Graph Triangle, if your points are correct, the answer area will appear. Click on the graph to plot a point. Click a point to delete it. x y N O P Find the desired slopes and lengths, then fill in the words that characterize the triangle. Answer Attempt 1 out of 2

slope of NO = slope of OP = slope of PN = length of NO = length of OP = length of PN = Triangle NOP is    Submit Answer  

Stuck? Copyright ©2024 DeltaMath.com All Rights Reserved.Privacy Policy | Terms of

Solution

To solve this problem, we'll determine the slopes and lengths of the sides of the triangle formed by the points N(5,5)N(5, 5), O(3,4)O(3, -4), and P(2,1)P(-2, -1). Then, we'll characterize the triangle based on its properties.


1. Slope Calculations

The slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

slope=y2y1x2x1.\text{slope} = \frac{y_2 - y_1}{x_2 - x_1}.

a) Slope of NONO:

slope of NO=4535=92=4.5.\text{slope of } NO = \frac{-4 - 5}{3 - 5} = \frac{-9}{-2} = 4.5.

b) Slope of OPOP:

slope of OP=1(4)23=35=0.6.\text{slope of } OP = \frac{-1 - (-4)}{-2 - 3} = \frac{3}{-5} = -0.6.

c) Slope of PNPN:

slope of PN=5(1)5(2)=670.857.\text{slope of } PN = \frac{5 - (-1)}{5 - (-2)} = \frac{6}{7} \approx 0.857.


2. Length Calculations

The distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

distance=(x2x1)2+(y2y1)2.\text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

a) Length of NONO:

length of NO=(35)2+(45)2=(2)2+(9)2=4+81=85.\text{length of } NO = \sqrt{(3 - 5)^2 + (-4 - 5)^2} = \sqrt{(-2)^2 + (-9)^2} = \sqrt{4 + 81} = \sqrt{85}.

b) Length of OPOP:

length of OP=(23)2+(1(4))2=(5)2+(3)2=25+9=34.\text{length of } OP = \sqrt{(-2 - 3)^2 + (-1 - (-4))^2} = \sqrt{(-5)^2 + (3)^2} = \sqrt{25 + 9} = \sqrt{34}.

c) Length of PNPN:

length of PN=(5(2))2+(5(1))2=(7)2+(6)2=49+36=85.\text{length of } PN = \sqrt{(5 - (-2))^2 + (5 - (-1))^2} = \sqrt{(7)^2 + (6)^2} = \sqrt{49 + 36} = \sqrt{85}.


3. Characterizing the Triangle

To characterize the triangle, compare slopes and side lengths:

  1. The slopes of NONO, OPOP, and PNPN are distinct, so the triangle is not right-angled.
  2. Two side lengths (85\sqrt{85}) are equal, and one side length (34\sqrt{34}) is different. Thus, the triangle is isosceles.

Final Answers:

  • Slope of NONO: 4.54.5
  • Slope of OPOP: 0.6-0.6
  • Slope of PNPN: 0.8570.857
  • Length of NONO: 85\sqrt{85}
  • Length of OPOP: 34\sqrt{34}
  • Length of PNPN: 85\sqrt{85}
  • Triangle NOPNOP is: Isosceles

Would you like more clarification or need assistance plotting the points on the graph?


Related Questions:

  1. How do you determine if a triangle is right-angled using slopes?
  2. What is the significance of calculating the slopes for triangle sides?
  3. How can you verify the isosceles property using side lengths?
  4. What are other methods to characterize a triangle using its vertices?
  5. Can you calculate the area of the triangle given these points?

Tip:

When finding slopes or lengths, always double-check signs for accuracy, especially when dealing with negative coordinates!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Analytic Geometry
Coordinate Geometry
Triangles

Formulas

Slope formula: (y2 - y1) / (x2 - x1)
Distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Properties of triangles
Isosceles triangle characterization

Suitable Grade Level

Grades 9-10