To calculate the area of the given triangle:

1. Identify the base and height:

   • The base of the triangle is $16 \, \text{cm}$.
   • The height of the triangle is $6 \, \text{cm}$.

2. Use the formula for the area of a triangle: $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$

3. Substitute the values: $\text{Area} = \frac{1}{2} \times 16 \times 6$

4. Simplify: $\text{Area} = 8 \times 6 = 48 \, \text{cm}^2$

Final Answer:

The area of the triangle is $48 \, \text{cm}^2$.

Let me know if you'd like a more detailed breakdown!

5 Related Questions:

1. How would the area change if the base was doubled while keeping the height the same?
2. What formula would you use if the triangle were a right triangle with only its two shorter sides given?
3. How can the Pythagorean theorem be used to verify the lengths in this diagram?
4. How do you calculate the area if only the angles and two sides are given?
5. If the height is halved, what would the new area of the triangle be?

Tip:

Always ensure that the base and height of a triangle are perpendicular to each other before using the area formula!