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The problem is asking for the value of angle \(x^\circ\) in a triangle where the other two angles are \(60^\circ\) and \(100^\circ\).

In a triangle, the sum of the interior angles is always \(180^\circ\). This means:

\[
60^\circ + 100^\circ + x^\circ = 180^\circ
\]

Now, solving for \(x\):

\[
x = 180^\circ - (60^\circ + 100^\circ) = 180^\circ - 160^\circ = 20^\circ
\]

Therefore, the value of \(x\) is \(20^\circ\).

So the correct answer is **B. 20**.

Would you like further explanation on this, or have any additional questions?

Here are 5 related questions to expand your understanding:

1. What is the sum of interior angles for any polygon?
2. How do we classify a triangle based on its angles?
3. How can you verify the internal angles of a triangle in a more complex geometric figure?
4. What happens if a triangle has two angles equal to \(90^\circ\) and \(30^\circ\)?
5. How does this concept apply to quadrilaterals and other polygons?

**Tip:** Always remember, for any triangle, the sum of the internal angles will always be \(180^\circ\).

What is the value of x in a triangle where two angles are 60° and 100°?

Learn how to find the value of x in a triangle where the other two angles are 60° and 100°. This geometry problem demonstrates the Triangle Angle Sum Theorem and the formula for the sum of interior angles in a triangle, which always equals 180°. Suitable for students in Grades 6-8.

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