Math Problem Statement
Solution
To solve this problem, we can begin by constructing a tree diagram based on the given probabilities:
-
Rain on a given day (today):
- The probability it rains the next day is .
- The probability it does not rain the next day is .
-
No rain on a given day:
- The probability it rains the following day is .
- The probability it does not rain is .
Step 1: Draw the Tree Diagram
We start from today, where it is raining:
- Day 1 (next day):
- If it rains, with probability :
- Day 2 (the following day):
- It rains again with probability .
- It does not rain with probability .
- Day 2 (the following day):
- If it does not rain, with probability :
- Day 2:
- It rains with probability .
- It does not rain with probability .
- Day 2:
- If it rains, with probability :
Step 2: Calculate Probabilities for Each Path
We want to calculate the probability of exactly one of the next two days being rainy:
-
Path: Rain on Day 1, No Rain on Day 2:
- Probability: .
-
Path: No Rain on Day 1, Rain on Day 2:
- Probability: .
Step 3: Add the Probabilities
Since these are mutually exclusive events (either the rain happens on Day 1 or Day 2, but not both), we add the probabilities:
Final Answer:
The probability that it will rain on exactly one of the next two days is .
Would you like further clarification, or should I break down any part of this solution in more detail?
Here are 5 related questions for further practice:
- What is the probability that it will rain on both of the next two days?
- What is the probability that it will not rain on either of the next two days?
- How would the probabilities change if the chances of rain on a rainy day were ?
- What is the probability that it rains on at least one of the next two days?
- How
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Math Problem Analysis
Mathematical Concepts
Probability
Conditional Probability
Tree Diagrams
Formulas
Probability of event A and event B: P(A and B) = P(A) * P(B|A)
Probability of event A or event B: P(A or B) = P(A) + P(B) - P(A and B)
Theorems
Law of Total Probability
Multiplication Rule for Independent Events
Suitable Grade Level
Grades 8-10